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SpyIntel [72]
2 years ago
14

A negative charge is paced in an electric field that points west. What direction is the force on the negative particle?

Physics
2 answers:
SIZIF [17.4K]2 years ago
8 0

Answer:

The force of the negative particle direction is East.

Greeley [361]2 years ago
4 0

Answer:

A positive charge placed in an electric field will tend to move in the direction of the electric field lines and a negative charge will tend to move opposite to the direction of the electric field lines.

One way to remember this is that there is one velocity, and so the thumb represents it. There are many field lines, and so the fingers represent them. The force is in the direction you would push with your palm. The force on a negative charge is in exactly the opposite direction to that on a positive charge.

Explanation:

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A young man exerted a force of 9,000 N on a stalled car but was unable to move it. How much work was done?
olasank [31]
W=F*s
W=9000*0
W=0
W:Work
F:Force
s:Distance
5 0
3 years ago
In what way do sound waves differ from radio waves?.
Akimi4 [234]
Radio waves are a type of electromagnetic wave that can travel when there is no medium, whereas sound waves are a type of mechanical wave that cannot travel if there is no medium
4 0
2 years ago
A coin is resting on the bottom of an empty container. The container is then filled to the brim three times, each time with a di
Virty [35]

Answer:

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

Explanation:

Let the depth of each section is h.

That means the real depth for each section is h.

Apparent depth is liquid A is 7 cm.

Apparent depth in liquid B is 6 cm.

Apparent depth in liquid C is 5 cm.

by the formula of the refractive index

n = real depth / apparent depth

where, n is the refractive index of the liquid.

For liquid A:

n_{A}=\frac{h}{7}    .... (1)

For liquid B:

n_{B}=\frac{h}{6}   ..... (2)

For liquid C:

n_{C}=\frac{h}{5}     ..... (3)

By comparing all the three equations

nc > nB > nA

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

5 0
3 years ago
A 20 kg box on a horizontal frictionless surface is moving to the right at a speed of 4.0 m/s. The box hits and remains attached
yanalaym [24]

Answer:

Work done by the spring is negative

Explanation:

We can answer this question by thinking what is the force acting on the box.

In fact, the force acting on the box is the restoring force of the spring, which is given by Hooke's Law:

F=-kx

where

k is the spring constant

x is the displacement of the box with respect to the equilibrium position of the spring

The negative sign in the equation indicates that the direction of the force is always opposite to the direction of the displacement: so, whether the spring is compressed or stretched, the force applied by the spring on the box is towards the equilibrium position.

The work done by the restoring force is also given by

W=Fx cos \theta

where

F is the restoring force

x is the displacement

\theta is the angle between the direction of the force and the displacement

Here we know that the force is always opposite to the displacement, so

\theta=180^{\circ} \rightarrow cos \theta =-1

Which means that the work done by the spring is always negative, since the direction of the restoring force is always opposite to the direction of motion.

7 0
3 years ago
Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equatio
yarga [219]

Answer:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)


Explanation:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

m(P4) = M(P4)*m(P4O10)/M(P4O10)
          = 123.90*105.8/283.89
          = 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
                = 10*122.55*105.8/283.89/3
                = 149 (grams).

6 0
2 years ago
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