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3 years ago

The two types of decomposers

Physics

1 answer:

ycow [4]3 years ago

6 0

Bacteria,Worms, Slugs, Snails, and Fungi are all types of decomposers

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The percentage of fe in an iron ii sample was determined by redox titration with cr2o7 calculate the molarity of the standard k2

Archy [21]

The molarity is 0.018M and the percentage is 8.46%.

Net ionic reaction is

$\mathrm{Cr} 2 \mathrm{O}^{2-}+6 \mathrm{Fe}^{2+}+14 \mathrm{H}^{+} \rightarrow 6 \mathrm{Fe}^{3+}+2 \mathrm{Cr}^{3+}+7 \mathrm{H} 2 \mathrm{O}$

$1 \mathrm{~mol}$ of $\mathrm{Cr} 2 \mathrm{O} 7(-2)$ reacts with $6 \mathrm{~mol}$ of $\mathrm{Fe}(2+)$ to form $6 \mathrm{~mol}$ of $\mathrm{Fe}(3+)$ and $2 \mathrm{~mol}$ of $\mathrm{Cr}(3+)$

Find molarity of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$

Molarity = moles of $\mathrm{K} 2 \mathrm{Cr} 207 /$ Volume of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7(\mathrm{~L}$ )

Moles of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$ = grams of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$ molar mass of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$

$=1.2275 \mathrm{~g} / 294.19 \mathrm{~mol}=0.0042 \mathrm{~g} / \mathrm{mol}$

Molarity of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7=$ moles of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$ / Volume of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$ (L)

$=0.0042 \mathrm{~g} / \mathrm{mol} / 0.250 \mathrm{~L}=0.017 \mathrm{M}$

Find molarity of $\mathrm{Fe}$ (II)

Molarity of $\mathrm{Fe}(\mathrm{II})=6 \times$ molarity of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 \times$ volume of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$ volume of $\mathrm{Fe}$ (II)

$=6 \times 0.017 \mathrm{M} \times 0.03598 \mathrm{~L} / 0.200 \mathrm{~L}$

$=0.018 \mathrm{M}$

Find moles of $\mathrm{Fe}(\mathrm{II})$

Moles of $\mathrm{Fe}($ II) =$ molarity of $\mathrm{Fe}$ (II) $\times$ volume of $\mathrm{Fe}$ (II)

$=0.018 \mathrm{M} \times 0.200 \mathrm{~L}=0.004 \mathrm{~mol}$

Find mass of Fe(II)

Mass of $\mathrm{Fe}( II )=$ moles of $\mathrm{Fe}( II$ ) $\times$ molar mass of $\mathrm{Fe}(\mathrm{II})$

$=0.004 \mathrm{~mol} \times 55.85 \mathrm{~g} / \mathrm{mol}$

$=0.205 \mathrm{~g}$

Find $\% \mathrm{Fe}(\mathrm{II})$ in unknown sample

$\begin{aligned}\% \mathrm{Fe} &=(\text { mass of } \mathrm{Fe} / \text { weight of unknown sample }) \times 100 \\&=(0.205 \mathrm{~g} / 2.4234 \mathrm{~g}) \times 100 \\&=8.46 \%\end{aligned}$

Molarity is the concentration of a solution expressed as the number of moles of solute dissolved in each liter of solution.

concentration is the amount of a substance per defined space. Concentration usually is expressed in terms of mass per unit volume.

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2 years ago

Based on all we know about the terrestrial worlds, what single factor appears to play the most important role in a terrestrial p

Archy [21]

Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .

According to the question

Terrestrial Planets:

They belongs to a class of planets that are like the earth

Geological destiny :

Geology is biological destiny: Whatever minerals land or are deposited in a place determine what or who can make a living there millions of years later

Based on all we know about the terrestrial worlds, what single factor appears to play the most important role in a terrestrial planet's geological destiny

i.e

The size of terrestrial planet is one of the factors to play the most important role in a terrestrial planet's geological destiny

which determines how long the planet can retain internal heat, which drives geological activity because Smaller worlds cool off faster and harden earlier .

Hence, Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .

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2 years ago

Which is equal to a temperature of 20°C? <br>20°F <br>68°F<br>36°F <br>32°F

Dahasolnce [82]

The correct answer would be 68°F because (20°C × 9/5) + 32 = 68°F.

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4 years ago

Read 2 more answers

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