Answer:
KE = 1/2*m*v^2
KE = 1/2*150kg*(20 m/s)^2
KE = 75kg * 400m²/s²
KE = 30,000 kg*m²/s²
KE = 30,000 N*m
KE = 30,000 J
Explanation:
Hope this helped.
A brainliest is always appreciated.
According to Kepler's second law of orbital motion, a plane's orbital speed changes , depending on how far it is from the sun. The closer a planet is to the sun, the stronger the sun's gravitational pull on it, and the faster the planet moves. The farther away from the sun, the weaker the sun's gravitational pull and the slower it moves in its orbit.
The orbit of a planet around the sun is not a perfect circle, but an ellipse - a flattened circle.
Answer:I belive it would be attracted seeing as how there are more magmatic charges on that side of no 2 and how there are more positive charges on the middle side of ballon no1.
Explanation:
At first sight it doesn't bode well. The key is in how firmly the protons and neutrons are held together. In the event that an atomic response produces cores that are more firmly bound than the firsts then vitality will be created, if not you should place vitality into make the response happen.
2.168 L of air will leave the container as it warms
<h3>Further explanation</h3>
Given
V₁=2.05 L
T₁ = 5 + 273 = 278 K
T₂ = 21 + 273 = 294 K
Required
Volume of air
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
Input the value :
V₂=(V₁.T₂)/T₁
V₂=(2.05 x 294)/278
V₂=2.168 L
