Answer:
The temperature change was 10.04 °C.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system. In this way, there is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case you know:
- c= 1
Replacing:
7,529 cal= 1 *750 g* ΔT
Solving you get:
ΔT=
ΔT= 10.04 °C
So, <u><em>the temperature change was 10.04 °C.</em></u>
The balanced equation :
<em>2Al₂O₃⇒ 4Al+3O₂</em>
<h3>Further explanation</h3>
Given
Reaction
Al₂O₃⇒ Al+O₂
Required
Balanced equation
Solution
A chemical reaction is said to be balanced if the number of elements involved in the reaction is the same (either the reactants or the products)
The reaction above is said to be unbalanced because the number of elements Al and O in the reactants and products is not the same.
The balancing step
1. Give a coefficient
Al₂O₃⇒ aAl+bO₂
2. Make an equation
Al, left = 2, right = a⇒a=2
O, left = 3, right = 2b⇒2b=3⇒b=3/2
The equation becomes :
Al₂O₃⇒ 2Al+3/2O₂ x2
<em>2Al₂O₃⇒ 4Al+3O₂</em>
The answer is a. The arteries are red and transfer blood to the heart. Veins are blue and transfer blood away from the heart and to all of the different parts of the body. The capillaries are in-between the veins and arteries and provide blood to cells.
Answer:
The acceleration of the car is -5m/s²
Explanation:
Given parameters:
Initial velocity = 75m/s
Final velocity = 0m/s
Time = 15s
Unknown:
Acceleration of the car = ?
Solution:
Acceleration is the rate of change of velocity with time;
Mathematically;
Acceleration = 
Insert parameters and solve,
Acceleration = 
= -5m/s²
The acceleration of the car is -5m/s²
Answer:
I think the answer is A) repeatedly testing the solubility at various temperatures
Explanation:
