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Artist 52 [7]
3 years ago
9

Clouds are formed by the ________ water

Chemistry
1 answer:
tatuchka [14]3 years ago
4 0
Clouds are made of water. When water evaporates it turns into clouds. So, I think the answer is EVAPORATED water.
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State one difference in the physical properties of the isotopes 63Cu and 65Cu and explain why their chemical properties are the
kupik [55]
Of the same element with different mass numbers are called isotopes 3) Isotopes have the same number of protons but different numbers of neutrons in their nuclei. ... The 63Cu isotope has 63 - 29 = 34 neutrons. The 65Cu isotope has 65 - 29 = 36 neutrons.
5 0
3 years ago
BRAINLIST!!
kolezko [41]

Answer:

D or C.

Explanation:

Sorry if its wrong

8 0
3 years ago
Pcl5 exist but ncl5 does not.why?
jeyben [28]
N is as electronegative as Cl is. So Cl doesnt react with O, N
6 0
3 years ago
What is the name of the molecule below?
Lostsunrise [7]

The name of the molecule above is <u>Ethene</u>

<h3>What are organic compounds?</h3>

Organic compounds can be defined as compounds containing carbon and hydrogen.

Some classes of organic compounds are:

  • Alkanes
  • Alkenes
  • Alkanols
  • Alkanals
  • Alkynes

So therefore, he name of the molecule above is Ethene

Learn more about organic compounds:

brainly.com/question/704297

#SPJ1

3 0
2 years ago
If 5.0 grams of sucrose, C12H22O11, are dissolved in 10.0 grams of water, what will be the boiling point of the resulting soluti
GaryK [48]

Answer : The boiling point of the resulting solution is, 100.6^oC

Explanation :

Formula used for Elevation in boiling point :

\Delta T_b=i\times k_b\times m

or,

T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of water = 100^oC

k_b = boiling point constant  = 0.52^oC/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute (sucrose) = 5.0 g

w_1 = mass of solvent (water) = 10.0 g

M_2 = molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

(T_b-100)^oC=1\times (0.52^oC/m)\times \frac{(5.0g)\times 1000}{342.3\times (10.0g)}

T_b=100.6^oC

Therefore, the boiling point of the resulting solution is, 100.6^oC

5 0
3 years ago
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