<u>169 Kcalories</u> are provided by a portion of food that has 25 grams of carbs, 6 grams of protein, and 5 grams of fat.
Kcalories mean kilo-calories. Basically, kilo-calorie or kcal refers to 1,000 calories. To get the Kcalories of food, you have to add the kcal of carbohydrates, protein, and fat.
Get the product by multiplying the number of grams of carbohydrate, protein, and fat by 4,4, and 9, respectively. So if you want to get the energy or Kcal available from a meal, you must then combine the outcomes.
Simply put it, take note of the following conversions:
- 1 gram of carbohydrate is 4kcal
- 1 gram of protein is also 4kcal
- Though, 1 gram of fat is 9kcal
So here's how to compute the Kcalories of food that contains 25g carbs, 6g protein, and 5g fat.
1. 25g x 4kcal/g = 100kcal
2. 6g x 4kcal/g = 24kcal
3. 5g x 9kcal/g = 45kcal
4. 100kcal + 24kcal + 45kcal = 169kcal!
Therefore, the food contains 169 kilo-calories!
You might be interested in nutrient density of an orange juice per kcalorie. Look here: brainly.com/question/26495283
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Answer:
Explanation:
Given
mass of core
Average specific heat 
And rate of increase of temperature =
Now
P=
Thus ![\frac{\mathrm{d}T}{\mathrm{d} t}=[tex]\frac{1.60\times 10^5\times 0.3349}{150\times 10^6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmathrm%7Bd%7DT%7D%7B%5Cmathrm%7Bd%7D%20t%7D%3D%5Btex%5D%5Cfrac%7B1.60%5Ctimes%2010%5E5%5Ctimes%200.3349%7D%7B150%5Ctimes%2010%5E6%7D)
F equals 3N with respect to the circle's center, moving in the same direction as the centripetal acceleration.
<h3>How much centripetal force is there in a centrifuge?</h3>
Centripetal force is the force that pushes an item in the direction of its center of curvature. It is fundamental to how a centrifuge operates.
<h3>On a roller coaster, what is centripetal force?</h3>
An item travelling in a circle is pushed inward toward what is known as the center of rotation, which is essentially what a roller coaster accomplishes when it travels through a loop. The force that maintains an object moving along a curved route is this pull toward the center, or centripetal force.
To know more about centripetal force visit:-
brainly.com/question/11324711
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Answer:
<h2>The angular velocity just after collision is given as</h2><h2>
</h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>
Explanation:
As per given figure we know that there is no external torque about hinge point on the system of given mass
So here we will have
now we can say
so we will have
Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass
So we can use angular momentum conservation about the hinge point
