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KengaRu [80]
3 years ago
14

"a 2.0-m straight wire carrying a current of 0.60 a is oriented parallel to a uniform magnetic field of 0.50 t. what is the magn

itude of the magnetic force on it? "
Physics
1 answer:
Oksana_A [137]3 years ago
8 0
The magnitude of the magnetic force acting on the wire is zero, because the magnetic field is parallel to the wire.

In fact, the magnetic force exerted by the magnetic field on the wire is
F=ILB \sin \theta
where I is the current in the wire, L the length of the wire, B the magnetic field intensity and \theta the angle between the direction of B and the wire. In our problem, B and the wire are parallel, so the angle is 0^{\circ} and so \sin \theta =0, therefore the magnetic force is zero: F=0.
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Answer:

The deceleration is  a =  - 76.27 m/s^2

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From the law of energy conservation

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and  KE_B is the kinetic energy of the person just before landing on the safety net  which is mathematically represented at

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Applying the equation o motion

             v_f =  v  + 2 a s

Now the final velocity is zero because the person comes to rest

      So

         0 = 16.57 + 2 * a * 1.8

            a =  - \frac{16.57^2 }{2 * 1.8}

            a =  - 76.27 m/s^2

         

         

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