Answer:
30% probability that it is either red or yellow
Step-by-step explanation:
We have that:
10% of the candies are green
10% of the candies are red
20% of the candies are yellow
20% of the candies are blue
20% of the candies are orange.
The rest is brown. The percentage of brown candies is not important to this problem.
If you pick a candy at random, what is the probability that it is either red or yellow?
10% are red
20% are yellow
10 + 20 = 30%
30% probability that it is either red or yellow
Answer:
an open circle on -1.3 on the line and draw a line to the right with an arrow.
Step-by-step explanation:
On your number line, draw an open circle on -1.3 and then draw a line on the number line going to the right and ending with an arrow at the end. The open circle means that it is that starting point, but is not equal to it.
Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
We are required to simplify the quotient: ![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D)
Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:
![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B60%7D%20%7B20%7D%7D)
![=\sqrt[3]{3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%7D)
The simplified form of the given quotient is .
Answer:
23.6666666667
Step-by-step explanation:
