Basically, when someone is resting in an accelerated vehicle without restraint from a seatbelt, the force of stopping the vehicle will be when inertia occurs, and that force of the vehicle coming to a stop will affect the passenger (without a seatbelt/restraint from another force or object) greatly by throwing them.
For example;
If I were to be riding in a vehicle (without a seatbelt) that's accelerating at 40 m/s^2 and it suddenly gets slammed on the breaks, I will be thrown forward from inside the vehicle.
I hope this helps!
Answer:

Explanation:
Work is given by the equation
where
is force and
is displacement.
Displacement is defined as change in position. In this case, the box moves from 5m to 20m. Its displacement is
.
The force acting on the box is the force of gravity, given as
.
Therefore, the total work done is:
(two significant figures).
Answer:
(a). The velocity of the object is -2.496 m/s.
(b). The total distance of the object travels during the fall is 23.80 m.
Explanation:
Given that,
Time = 1.95 s
Distance = 23.5 m
(a). We need to calculate the velocity
Using equation of motion

Put the value into the formula



(b). We need to calculate the total distance the object travels during the fall
Using equation of motion

Put the value in the equation



The total time is


We need to calculate the distance
Using equation of motion

Put the value into the formula


Hence, (a). The velocity of the object is -2.496 m/s.
(b). The total distance of the object travels during the fall is 23.80 m.
Resultant force= (2*6^2)^(1/2)
=8.5m/s
answer is B.