Answer:
a) final angular speed w2 = 414rpm
b) time to stop t = 312.5s
c) angular distance from start to stop s = s = 1171.88 rev
Explanation:
Average angular speed wa = (w1+w2)/2 = Angular distance/time = s/t
Given;
w1 = 450 rpm = 450/60 rev/s = 7.5 rev/s
s = 180 rev
t = 25s
a)
s/t = (w1+w2)/2
w2 = 2s/t - w1
Substituting the values;
w2 = 2×180/25 - 7.5 = 6.9 rev/s
w2 = 6.9×60rpm = 414rpm
b)
Angular deceleration a = (w1-w2)/t = (7.5-6.9)/25
a = 0.024 rev/s^2
time t for w2 = 0
t = (w1-w2)/a = (7.5-0)/0.024
t = 312.5 s
c)
Angular distance from start to stop s;
s = w1t - 0.5at^2
s = 7.5×312.5s - 0.5×0.024×312.5^2
s = 1171.88 rev
Answer:she should consider the time on how long it would take to move it and where she will move it
Explanation:
hope this helps
- At pole the gravitation is more than that of equator .
And according to newtons second law
Force=Mass×Acceleration
And
- Hence force varies directly with acceleration hence weight will be more .
Answer:
The reason is similar to the reason why it is difficult to roll an object on a surface with a positive incline than rolling it on the ground
The more the path becomes vertical, the more force we have to apply to oppose the force of gravity
but when we are moving horizontally, we don't have to move against the gravity and hence, it is less difficult than going vertically upwards
Answer:
The minimum number of 100 Ω resistors that i need to design an effective resistor with 275Ω resistance are 8 resistors.
Explanation:
(2 Resistors of 100Ω in parallel) in <u>series with</u> (4 resistors of 100Ω in parallel) in <u>series</u> with 2 resistors of 100Ω.
2 resistors in parallel of 100Ω = 50Ω
+
4 resistors in parallel of 100Ω = 25Ω
+
2 resistors in series of 100 2Ω = 200Ω
=
275Ω