Answer: time taken to charge to 95%
t = -5.80[ln(1-0.95)]
t = 17.38ms
Explanation:
For an RC Charging circuit
Where Vs
Vc = Vs (1 - e^(-t/RC))
Vc/Vs = 1 - e^(-t/RC)
-t/RC = ln(1 - Vc/Vs)
t = -RC[ln(1 - Vc/Vs)] and RC = k = -t/ln(1 - Vc/Vs)
Where ;
Vc = voltage across the capacitor
Vs = voltage supply
t = charging time = 2.5ms
k = RC = time constant.
Vc/Vs = 0.35
To calculate the time constant k;
k = -t/ln(1- Vc/Vs)
k = -2.5/ln(1-0.35)
k = 5.80ms
time taken to charge to 95%
t = -5.80[ln(1-0.95)]
t = 17.38ms
The pressure on the diver is given by:
where F is the force exerted by the water on the diver, while A is the area of the diver.
In this problem, we know the pressure: 
, and the area of the diver, 
, therefore we can rearrange the initial equation to find the force on the diver:
Milliliters would be used to find the volume AKA amount of liquid
;Net force = mass of the body × acceleration of the body due to the net force
; 5000 = 2500 a...then divide both sides by 2500
; acceleration(a) = 2 m/s^2
