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Ksenya-84 [330]
2 years ago
13

Many bugs can reproduce both sexually and asexually. When would asexual reproduction be

Physics
1 answer:
azamat2 years ago
5 0

Answer:

try this

Sexual reproduction produces more offspring than asexual reproduction.

Asexual reproduction is a simpler process than sexual reproduction.

Sexual reproduction requires a single parent.

Asexual reproduction occurs when two gametes fuse.

Explanation:

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An arrow is moving at 35 m/s and travels for 5 seconds. how far did the arrow travel?
pashok25 [27]
The answer is 175 meters
8 0
3 years ago
Two or more velocities add by ____?<br><br> Plz help
VladimirAG [237]
By vector addition.
In fact, velocity is a vector, with a magnitude intensity, a direction and a verse, so we can't simply do an algebraic sum of the two (or more velocities). 
First we need to decompose each velocity on both x- and y-axis (if we are on a 2D-plane), then we should do the algebraic sum of all the components on the x- axis and of all the components on the y-axis, to find the resultants on x- and y-axis. And finally, the magnitude of the resultant will be given by
R= \sqrt{(R_x)^2+(R_y)^2}
where Rx and Rx are the resultants on x- and y-axis. The direction of the resultant will be given by
\tan \alpha =  \frac{R_y}{R_x}
where \alpha is its direction with respect to the x-axis.
3 0
3 years ago
Read 2 more answers
A small grinding wheel has a moment of inertia of 4.0*10-5kgm2. What net torque must be applied to the wheel for its angular acc
kvv77 [185]

Hi there!

We can use the rotational equivalent of Newton's Second Law:

\huge\boxed{\Sigma \tau = I \alpha}

Στ = Net Torque (Nm)

I = Moment of inertia (kgm²)

α = Angular acceleration (rad/sec²)

We can plug in the given values to solve.

\Sigma \tau = (4 * 10^{-5})(150) = \boxed{0.006 Nm}

4 0
2 years ago
An object of mass 25kg is falling from the height h=10 m. calculate
r-ruslan [8.4K]

Answer:

a=2500J,b=1000K,c=1000J,d=14.142m/s

Explanation:

V²=U²+2gh

V²=0 + 2×10×10=200m/s

a).kinetic energy=(1/2)mv²=(1/2)25×200=2500

potential energy=mgh

p.e=25×10×10=2500J

pe+ke=2500+2500=5KJ

b).mgh=25×10×4=1000J

c). V²=U²+2gh

V²=0+2×10×4

V²=80

kinetic energy=(1/2)mv²

=(1/2)25×80

=1KJ

d). From my first paragraph V²=200

V=√200

V=14.142m/s

6 0
3 years ago
Which quantity best describes this description? Justin walks at 3 miles per hour north, and then speeds up to 4 miles per hour.
prisoha [69]

Personally, I agree with your answer, namely that the likely-intended event happening here is one of acceleration. Having said that, I also want to add: it pains me to see this type of wording because, clearly, it is vague and only invites confusion of the type you are talking about.

Good luck!

4 0
3 years ago
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