Answer: 8*10^-15 N
Explanation: In order to calculate the force applied on an electron in the middle of the two planes at 500 V we know that, F=q*E
The electric field between the plates is given by:
E = ΔV/d = 500 V/0.01 m=5*10^3 N/C
the force applied to the electron is: F=e*E=8*10^-15 N
Answer:
They have same density
Explanation:
The density of an object is defined as
where
m is the mass of the object
V is its volume
Let's call 
and 
the mass and the volume of ball C, respectively. Therefore, the density of ball C is:
We know that the volume of ball C is 3 times the volume of ball D, so
And we also know that ball D has 1/3 the mass of ball C:
So, the density of ball D is:
Therefore, the two balls have same density.
When action potentials reach the end of the axon, they stimulate opening of Ca2+ channels, causing a release of neurotransmitters to the post-synaptic cell. How does and impulse propagate down the axon? The stimulus causes a start of the action potential and it moves down the axon without the ions moving down
