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padilas [110]
3 years ago
11

Most cancer-causing air pollutants are found outdoors. True False

Physics
2 answers:
natta225 [31]3 years ago
8 0
This is most likely True. However, it could be also False. Let me explain. 

There are many air pollutants that can be found outdoors and indoors. It does depend on what kind of indoor environment we're talking about. And also what kind of outdoor environment we're talking about. In both cases it depends on the context. If the indoor environment is quite toxic, then of course, there would be less cancer-causing air pollutants for a person outside. And the same is true for the other way around. 
Step2247 [10]3 years ago
6 0

On Odyssseyware its false.

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Un niño amarra una soga a una piedra, y la hace girar como en la gráfica. la piedra realiza un M.C.U, girando con una rapidez de
inessss [21]

Answer:

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

Explanation:

El ángulo barrido en el intervalo de tiempo dado es (The covered angle in the given time interval is):

\Delta \theta = \omega \cdot \Delta t

\Delta \theta = \left(14\,\frac{rad}{s} \rjght)\cdot (4\,s)

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

4 0
3 years ago
A 500-g lump of clay is dropped onto a 1-kg cart moving at 60 cm/s. The clay is moving downward at 30 cm/s just before l dith t
viktelen [127]

Answer:

The speed of the cart and clay after the collision is 50 cm/s .

Explanation:

Given :

Mass of lump , m = 500 g = 0.5 kg .

Velocity of lump , v = 30 cm/s .

Mass of cart , M = 1 kg .

Velocity of cart , V = 60 cm/s .

We know by conservation of momentum :

mv+MV=(m+M)v'

Here , v' is the speed of the cart and clay after the collision .

Putting all value in above equation .

We get :

0.5\times 30+1\times 60=(0.5+1)\times v'\\\\v'=\dfrac{15+60}{1.5}\\\\v'=50\ cm/s

Hence , this is the required solution .

3 0
3 years ago
A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no apprecia
Elenna [48]

Answer:A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no ..

6 0
2 years ago
A horizontal disk rotates about a vertical axis through its center. Point P is midway between the center and the rim of the disk
hjlf

Answer:

The answer is explained below.

Explanation:

All the point on the disk has same angular acceleration. Here, the point P is at the midway between the center and the rim of the disk and the point Q is at rim of the disk.

So, the distance of the point Q from the axis is twicee the distance of the point P from the axis.

<em>Rp - R</em>

<em>Rq - 2R</em>

The linear acceleration is

α2 - Rα

So, the linear acceleration of Q is twice as great as the linear acceleration of P.

The speed of the particle when it is in the circular motion depends on the radius of the particle.

In this case, the speed of point Q is twice the speed of point P.

6 0
3 years ago
Two thin rectangular sheets (0.16 m x 0.44 m) are identical. In the first sheet the axis of rotation lies along the 0.16-m side,
malfutka [58]

Answer:

t'=1.124s

Explanation:

I_b*a_b=I_a*a_a

a_a=\frac{w_f}{t'}

a_b=\frac{w_f}{t}

I_b*\frac{w_f}{t}=I_a*\frac{w_f}{t'}

I_b*\frac{1}{t}=I_a*\frac{1}{t'}

I=\frac{1}{3}*M*r^2

I_a=\frac{1}{3}*M*r_a^2

I_b=\frac{1}{3}*M*r_b^2

\frac{1}{3}*M*r_b^2*\frac{1}{t}=\frac{1}{3}*M*r_a^2*\frac{1}{t'}

t'=(\frac{r_a}{r_b})^2 *t

t'=(\frac{0.16m}{0.44m})^2*t

t'=\frac{16}{121}*8.5s

t'=1.124s

7 0
3 years ago
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