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3 years ago

Most cancer-causing air pollutants are found outdoors. True False

2 answers:

8 0

This is most likely True. However, it could be also False. Let me explain.

There are many air pollutants that can be found outdoors and indoors. It does depend on what kind of indoor environment we're talking about. And also what kind of outdoor environment we're talking about. In both cases it depends on the context. If the indoor environment is quite toxic, then of course, there would be less cancer-causing air pollutants for a person outside. And the same is true for the other way around.

Step2247 [10]3 years ago

6 0

On Odyssseyware its false.

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The water from a fire hose follows a path described by y equals 3.0 plus 0.8 x minus 0.40 x squared (units are in meters). If

ivanzaharov [21]

Explanation:

It is given that, the water from a fire hose follows a path described by equation :

$y=3+0.8x-0.4x^2$ ........(1)

The x component of constant velocity, $v_x=5\ m/s$

We need to find the resultant velocity at the point (2,3).

Let $\dfrac{dx}{dt}=v_x$ and $\dfrac{dy}{dt}=v_y$

Differentiating equation (1) wrt t as,

$\dfrac{dy}{dt}=0.8\times \dfrac{dx}{dt}-0.8x\times \dfrac{dx}{dt}$

$v_y=0.8\times v_x-0.8x\times v_x$

$v_y=0.8v_x(1-x)$

When x = 2 and $v_x=5\ m/s$

So,

$v_y=0.8\times 5\times (1-2)$

$v_y=-4\ m/s$

Resultant velocity, $v=\sqrt{v_x^2+v_y^2}$

$v=\sqrt{5^2+(-4)^2}$

v = 6.4 m/s

So, the resultant velocity at point (2,3) is 6.4 m/s. Hence, this is the required solution.

8 0

3 years ago

A microphone receiving a pure sound tone feeds an oscilloscope, producing a wave on its screen. If the sound intensity is origin

Temka [501]

Answer:

The new intensity = 3.38 × 10⁻⁵ W/m²

Explanation:

Intensity of sound wave:

The intensity of sound is the rate of flow of flow of energy, per unit area, perpendicular to the direction of the sound wave.

Intensity (I) ∝ A²

where I = intensity, A = Amplitude.

∴ I₁/I₂ = A₁²/A²₂............................... equation 1

From the question, the amplitude increase by 30% of the initial

∴ A₂ = A₁ + 0.3A₁ = 1.3A₁, I₁ = 2.00×10⁻⁵ W/m²

∴ (2.00×10⁻⁵)/I₂ = A₁²/(1.3A₁)²

(2.00×10⁻⁵)/I₂ = 1/1.3²

making I₂ the subject of the equation

I₂ = (2.00 × 10⁻⁵)×1.3² = 3.38 × 10⁻⁵ W/m₂

The new intensity = 3.38 × 10⁻⁵ W/m²

7 0

3 years ago

Light of wavelength 500 nm falls normally on 50 slits that are 2.5×10−3mm wide and spaced 5.0×10−3mm apart. How many interferenc

yanalaym [24]

Answer:

Explanation:

The solution is in the attached files below

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3 years ago

Hi I need help with this question (see image ).

Lapatulllka [165]

Explanation:

a) <em>Fixed points</em> are the temperatures at which a thermometer is calibrated. They can refer either to the actual temperatures used for calibration, or the thermometer readings at those temperatures.

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3 years ago

When Stone B collides with Stone A during Test 2, Stone B stops and Stone A begins to move. Which statement BEST describes the m

Anna11 [10]

Answer:

Explanation:

According to law of conservation of momentum, the total momentual in the system will be conserved

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2 years ago