Question

The electric potential at a point that is halfway between two identical charged particles is 300 V. What is the potential at a point that is 25% of the way from one particle to the other?

Answer 1

Answer:

The potential at a point is 400 V.

Explanation:

Given that,

The electric potential at a point that is halfway between two identical charged particles is 300 V

Potential V= 300 V

Let the distance between the charge is 2r.

The potential at mid point

Using formula of potential

$V=\dfrac{kq}{r}$

At mid point,

$V=V'+V''$

$V=\dfrac{kq}{r}+\dfrac{kq}{r}$

$\dfrac{2kq}{r}=300$...(I)

If the potential at a point that is 25% of the way from one particle to the other

We need to calculate the distance between the charge

$d=2r\times\dfrac{25}{100}$

$d=\dfrac{r}{2}$

We need to calculate the new potential

Using formula of potential again

$V=V'+V''$

$V=\dfrac{kq}{\dfrac{r}{2}}+\dfrac{kq}{\dfrac{3r}{2}}$

$V=\dfrac{2kq}{r}+\dfrac{2kq}{3r}$

$V=\dfrac{2kq}{r}(1+\dfrac{1}{3})$

Put the value of $\dfrac{2kq}{r}$

$V=300\times(1+\dfrac{1}{3})$

$V=400\ V$

Hence, The potential at a point is 400 V.