Study the scenario. The particles in a system are moving around very slowly. A few minutes later, the particles are moving, on a
1 answer:
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Answer : The correct option is, (B) 0.11 M
Solution :
First we have to calculate the concentration and
.
The given equilibrium reaction is,
Initially 0.70 0.70 0
At equilibrium (0.70-x) (0.70-x) x
The expression of will be,
Now put all the given values in the above expression, we get:
By solving the term x, we get
From the values of 'x' we conclude that, x = 0.83 can not more than initial concentration. So, the value of 'x' which is equal to 0.83 is not consider.
Thus, the concentration of at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M
The concentration of at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M
The concentration of at equilibrium = x = 0.59 M
Therefore, the concentration of at equilibrium is 0.11 M