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irakobra [83]
3 years ago
7

Study the scenario. The particles in a system are moving around very slowly. A few minutes later, the particles are moving, on a

verage, much faster. How does this change in motion affect the temperature of the system? the temperature increase since the average kinetic energy of the particles increases the temperature remains the same since temperature is a measure of potential energy of a system, not the movement of its particles it is not possible to tell since temperature is a result of the fastest moving particles in a system, not the average the temperature decreases since the average kinetic energy of the particles increases
Chemistry
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

The average kinetic energy of the system has increased as a result of the temperature increasing.

Explanation:

Assuming this is a gas based on the framing.

The molecules of a gas span a distribution of speeds, and the average kinetic energy of the molecules is directly proportional to the absolute temperature of the sample. KEavg is proportional to T.

This can be further studied until the Kinetic-Molecular Theory.

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What type of central-atom orbital hybridization corresponds to each electron-group arrangement:
galina1969 [7]

Tetrahedral arrangement is resulted upon mixing one s and three p atomic orbitals, resulting in 4 hybridized sp^3 orbitals → sp^3 hybridization.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about Hybridization

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3 0
2 years ago
An atom has an average atomic mass of about 63.5 amu. What is the chemical symbol for the atom? Consult the periodic table.
Mama L [17]
The best and most correct answer among the choices provided by your question is the fourth choice.

Copper <span>has an average atomic mass of about 63.5 </span>amu<span>.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
8 0
3 years ago
Read 2 more answers
What is the concentration if 20 grams of NaOH was dissolved in enough water to make a 250 mL NaOH solution?
gizmo_the_mogwai [7]

Answer: 1 molar NaOH contains 40 grams of NaOH per every liter of water

Explanation:

so 2 M NaOH contains twice that amount, ie. 80 grams per liter. Then, ine 250 ml of weater, there should be 80/4 = 20 grams of solid NaOH dissolved.

3 0
3 years ago
In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe
const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = 10^{-9} m.

Hence, 0.283 nm = 0.283 \times 10^{-9} m

  • Formula for coulombic energy is as follows.

             U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}

where,   e = 1.6 \times 10^{-19} C

            \epsilon_{o} = 8.85 \times 10^{-12}

          U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}

                         = 1.423 \times 10^{-18} J

  • As 1 eV = 1.6 \times 10^{-19} J

So,       1 J = \frac{1 eV}{1.6 \times 10^{-19}}

Hence,    U = \frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}

                   = 8.9 eV

  • Also,   1 J = \frac{10^{-3} kJ}{6.022 \times 10^{23}mol}

                = 1.67 \times 10^{-27} kJ/mol

Therefore, U = 1.423 \times 10^{-18} J \times 1.67 \times 10^{-27} kJ/mol

                     = 2.37 \times 10^{-45} kJ/mol

7 0
3 years ago
• What policies might people put in place to conserve water levels in lakes and aquifers?
vladimir2022 [97]

Some policies they might do is to put limits on water usage, like making sure that people don't use too much water in baths and when they are tending to their gardens.

7 0
4 years ago
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