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Serga [27]
3 years ago
14

You are standing in a street corner. And egg falls and splats on the street. Being an expert in egg disintegration you estimate

it was traveling 22 m/s when it hit. You assume the egg was dropped. From what height was it dropped
Physics
1 answer:
Alex787 [66]3 years ago
8 0

The egg was dropped from a height of 24.7 m (free fall motion)

Explanation:

The motion of the egg is a free fall motion (uniformly accelerated motion), so we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the egg in this problem, we have:

u = 0 is the initial velocity

v = 22 m/s is the final velocity

a=g=9.8 m/s^2 is the acceleration of gravity

s is the vertical displacement (the height from which the egg was dropped)

Solving for s, we find:

s=\frac{v^2-u^2}{2a}=\frac{22^2-0}{2(9.8)}=24.7 m

Learn more about free fall here:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

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Helga [31]

Answer:

ε = 2 V/cm

Explanation:

To calculate the mobility inside this bar, we just need to apply the expression that let us determine the mobility. This expression is the following:

ε = ΔV / L

Where:

ε: Hole mobility inside the bar

ΔV: voltage applied in the bar

L: Length of the bar

We already have the voltage and the length so replacing in the above expression we have:

ε = 2 V / 1 cm

<h2>ε = 2 V/cm</h2><h2></h2>

The data of the speed can be used for further calculations, but in this part its not necessary.

Hope this helps

8 0
3 years ago
Three joggers are running along straight lines as follows: Jogger A, with a mass of 55.2kg, is traveling along the line y=6.00m
frutty [35]

Answer:

L = - 1361.591 k Kgm/s

Explanation:

Given

mA = 55.2 Kg

vA = 3.45 m/s

rA = 6.00 m

mB = 62.4 Kg

vB = 4.23 m/s

rB = 3.00 m

mC = 72.1 Kg

vC = 4.75 m/s

rC = - 5.00 m

then we apply the equation

L =  (mv x r)

⇒  LA = mA*vA x rA = 55.2 *(3.45 i)x(6 j) = (1142.64 k) Kgm/s

⇒  LB = mB*vB x rB = 62.4 *(4.23 j)x(3 i) = (- 791.856 k) Kgm/s

⇒  LC = mC*vC x rC = 72.1 *(- 4.75 j)x(- 5 i) = (- 1712.375 k) Kgm/s

Finally, the total counterclockwise angular momentum of the three joggers about the origin is

L = LA + LB + LC = (1142.64 - 791.856 -1712.375) k  Kgm/s

L = - 1361.591 k Kgm/s

7 0
3 years ago
What is the frequency of this wave?
Reptile [31]
It’s 4 because a coiled springs is closely spaced then widen
3 0
3 years ago
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A vector has an x-component
9966 [12]

Explanation:

The magnitude of a vector v can be found using Pythagorean's theorem.

||v|| = √(vₓ² + vᵧ²)

||v|| = √((-309)² + (187)²)

||v|| ≈ 361

You can find the angle of a vector using trigonometry.

tan θ = vᵧ / vₓ

tan θ = 187 / -309

θ ≈ 149° or θ ≈ 329°

vₓ is negative and vᵧ is positive, so θ must be in the second quadrant.  Therefore, θ ≈ 149°.

4 0
3 years ago
A child is riding a merry-go-round that is turning at 7.18 rpm. If the child is standing 4.65 m from the center of the merry-go-
iVinArrow [24]

Answer:

B) 3.50 m/s

Explanation:

The linear velocity in a circular motion is defined as:

v=\omega r(1)

The angular frequency (\omega) is defined as 2π times the frequency and r is the radius, that is, the distance from the center of the circular motion.

\omega=2\pi f(2)

Replacing (2) in (1):

v=2\pi fr

We have to convert the frequency to Hz:

7.18rpm*\frac{1Hz}{60rpm}=0.12Hz

Finally, we calculate how fast is the child moving:

v=2\pi(0.12Hz)(4.65m)\\v=3.5\frac{m}{s}

3 0
3 years ago
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