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Serga [27]
3 years ago
14

You are standing in a street corner. And egg falls and splats on the street. Being an expert in egg disintegration you estimate

it was traveling 22 m/s when it hit. You assume the egg was dropped. From what height was it dropped
Physics
1 answer:
Alex787 [66]3 years ago
8 0

The egg was dropped from a height of 24.7 m (free fall motion)

Explanation:

The motion of the egg is a free fall motion (uniformly accelerated motion), so we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the egg in this problem, we have:

u = 0 is the initial velocity

v = 22 m/s is the final velocity

a=g=9.8 m/s^2 is the acceleration of gravity

s is the vertical displacement (the height from which the egg was dropped)

Solving for s, we find:

s=\frac{v^2-u^2}{2a}=\frac{22^2-0}{2(9.8)}=24.7 m

Learn more about free fall here:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

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