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2 years ago

Y is inversely proportional to x and x = 10 when y = 6 what is the value of the consant? k =

Mathematics

1 answer:

Papessa [141]2 years ago

7 0

Answer:

Step-by-step explanation:

y = k/x ( as y is inversely proportional to x)

yx = k

--> k = yx

k = (6)(10)

k = 60

Enjoy it. I hope it will help you.

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Find the volume of the figure.

NARA [144]

Answer:

Step-by-step explanation:

Volume of the figure = Volume of cone + Volume of hemisphere

Cone:

height h = 33 m

Diameter = 30m

Radius r = 30/2 = 15 m

Volume of Cone:

$=\frac{1}{3}\pi r^{2}h\\\\=\frac{1}{3}\pi*15*15*33\\\\=\pi*15*15*11\\\\=2475\pi m^{2}$

Hemisphere:

Radius r = 15 m

Volume of Hemisphere =

$=\frac{2}{3}\pi*r^{3}\\\\=\frac{2}{3}\pi*15*15*15\\\\=2*\pi*5*15*15\\\\=2250\pi$

Volume of the figure = 2475π + 2250π = 4725π m²

3 0

2 years ago

What is the standard deviation of the data set? 1, 4, 2, 2, 8, 7, 3 Round your answer to the nearest tenth.

fomenos

The Answer is 2.7 For Sure

4 0

2 years ago

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What is the value of 3ab+5b-6 when a=-1 and b=3?<br> A.0<br> B.6<br> C.18<br> D.24

Otrada [13]

Answer:

A. 0

Step-by-step explanation:

3ab+5b-6

= 3(-1)(3)+5(3)-6

=3(-3)+15-6

=-9+9

=0 ( you have to subtract because they don't have the same signs)

5 0

3 years ago

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How do you integrate arctan(x dx? i think that if you simplify the integral you get:?

Temka [501]

Integration by parts will help here. Letting $u=\arctan x$ and $\mathrm dv=\mathrm dx$ , you end up with $\mathrm du=\dfrac{\mathrm dx}{1+x^2}$ and $v=x$ . Now

$\displaystyle\int\arctan x\,\mathrm dx=uv-\int v\,\mathrm du$
$\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\int\frac x{1+x^2}\,\mathrm dx$

For the remaining integral, setting $y=1+x^2$ gives $\dfrac{\mathrm dy}2=x\,\mathrm dx$ , so

$\displaystyle\int\frac x{1+x^2}\,\mathrm dx=\frac12\int\frac{\mathrm dy}y=\frac12\ln|y|+C=\frac12\ln(1+x^2)+C$

Putting everything together, you end up with

$\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\frac12\ln(1+x^2)+C$

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2 years ago

Do me a favor everyone: While you're waiting for an answer to your answer, go through the feed page's questions and report every

azamat

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2 years ago

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