<span>Each atom contains an equal number of protons and electrons; these particles will be equal in value to an element's atomic number</span>
Answer:
A) 1.67 x 10 ⁻⁶ m/s
B)5.59 x
%
Explanation:
A)
Given:
d = 5.0 km,
mₐ = 2.5 x
kg
u₁ = 4.0 x 10⁴ m/s
= 5.98 x 10 ²⁴ kg
Solve using kinetic conserved energy
mₐ x u₁ +
x u₂ = uₓ x (mₐ +
)
(2.5 x
) (4.0 x 10⁴ )+ (5.98 x 10 ²⁴ )(0) = uₓ x (2.5 x
+ 5.98 x 10 ²⁴ )
uₓ = ( 2.5 x
x 4.0 x 10⁴ ) / (2.5 x
+ 5.98 x 10 ²⁴ )
uₓ = 1.67 x 10 ⁻⁶ m/s
B) Assuming earth radius as a R = 1.5 x 10 ¹¹ m
t = 365 days x 24 hr / 1 day x 60 minute / 1 hr x 60s / 1 minute = 31536000 s
t = 31536000 s
D = 2 π R = 2 π( 1.5 x 10 ¹¹ )
D = 9.4247 x 10 ¹¹ m
u₂ = D / t = 9.4247 x 10 ¹¹ / 31536000
u₂ = 29885.775 m/s
% = ( 1.67 x 10 ⁻⁶ m/s ) / (29885.775 m/s) x 100
% = 5.59 x
%
Answer:
Explanation:
Given
mass of ice 
Final temperature of liquid 
Specific heat of water 
Latent heat of fusion 
Latent heat of vaporization 
Suppose M is the mass of steam at 
Heat required to melt ice and convert it to water at 

Heat released by steam

and
must be equal as the heat gained by ice is equal to Heat released by steam


![\Rightarrow M=\dfrac{m[L+c\times T_f]}{L_v+c(100-T_f)}](https://tex.z-dn.net/?f=%5CRightarrow%20M%3D%5Cdfrac%7Bm%5BL%2Bc%5Ctimes%20T_f%5D%7D%7BL_v%2Bc%28100-T_f%29%7D)
![\Rightarrow M=\dfrac{119[333\times 10^3+4186\times 57]}{2256\times 10^3+4186\times (100-57)}](https://tex.z-dn.net/?f=%5CRightarrow%20M%3D%5Cdfrac%7B119%5B333%5Ctimes%2010%5E3%2B4186%5Ctimes%2057%5D%7D%7B2256%5Ctimes%2010%5E3%2B4186%5Ctimes%20%28100-57%29%7D)


Answer:
630 Hz.
Explanation:
As we are considering the one end open pipe. So for the sound wave there will be a pressure node at the open end of the tube as at that place the molecules can not move back and forth. However on the closed end there will be a flow node as the water molecules their are moving back and forth. So it will produces the resonance at the positions 1/4, 3/4.......
we can find the wavelength by multiplying the levels distance by 2.
λ = 2 × 0.27 m = 0.54
f = Vs/λ
= 340/0.54
= 630 Hz