The answer is slightly left and slightly right of the curved end of the horseshoe.
Answer:
The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s
Explanation:
From Newton's second law, F = mg and also from coulomb's law F= Eq
Dividing both equations by mass;
F/m = Eq/m = mg/m, then
g = Eq/m --------equation 1
Again, in a projectile motion, the time of flight (T) is given as
T = (2usinθ/g) ---------equation 2
Substitute in the value of g into equation 2

Charge of proton = 1.6 X 10⁻¹⁹ C
Mass of proton = 1.67 X 10⁻²⁷ kg
E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°
Solving for T;

T = 7.83 X10⁻⁷ s
Answer:
23.8 m
Explanation:
The distance travelled by the zebra can be calculated by using the equation:

where
u is the initial velocity
t is the time
a is the acceleration
For this zebra,
u = 0 since it starts from rest
is the acceleration
Substituting t = 5 s, we find the distance travelled by the zebra:

This is very low little to no proper bailout