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oksian1 [2.3K]
3 years ago
14

Which of the following occurs in January when the earth is closest to the sun?

Physics
1 answer:
Vlada [557]3 years ago
4 0
Its January 4th 2003
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Where is the magnetic field of a horseshoe magnet the strongest?<br> pls hellp omg
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3 years ago
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A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a
GuDViN [60]

Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

Explanation:

From Newton's second law, F = mg and also from coulomb's law F= Eq

Dividing both equations by mass;

F/m = Eq/m = mg/m, then

g = Eq/m --------equation 1

Again, in a projectile motion, the time of flight (T) is given as

T = (2usinθ/g) ---------equation 2

Substitute in the value of g into equation 2

T = \frac{2usin \theta}{\frac{Eq}{m}} =\frac{m* 2usin \theta}{Eq}

Charge of proton = 1.6 X 10⁻¹⁹ C

Mass of proton = 1.67 X 10⁻²⁷ kg

E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°

Solving for T;

T = \frac{(1.67X10^{-27}* 2*3X10^4sin 30}{400*1.6X10^{-19}}

T = 7.83 X10⁻⁷ s

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3 years ago
Most ocean waves obtain their energy and motion from _____. the wind the moon’s gravitational attraction the sun plate movement
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A zebra starts from rest and accelerates at 1.9 m/s, how far has the zebra gone after 5 seconds
Aliun [14]

Answer:

23.8 m

Explanation:

The distance travelled by the zebra can be calculated by using the equation:

d=ut+\frac{1}{2}at^2

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For this zebra,

u = 0 since it starts from rest

a=1.9 m/s^2 is the acceleration

Substituting t = 5 s, we find the distance travelled by the zebra:

d=0+\frac{1}{2}(1.9)(5)^2=23.8 m

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The probability of an event A occurring is 0.73.
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This is very low little to no proper bailout
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