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True [87]
3 years ago
15

Instructions

Chemistry
1 answer:
Marysya12 [62]3 years ago
7 0

Answer:

-104.7?

I really dont know sorry :/

Explanation:

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How would u describe the shape of a big drop of water. Thanks everyone for your help
Furkat [3]

Answer:

It is a semi circle with a triangle on top

6 0
3 years ago
Ten pints of 15 % salt solution are mixed with 15 pints of 10 % salt solution. What is the
sergij07 [2.7K]
Concentration\ rate=\frac{mass\ of\ product}{mass\ of\ substance}*100\%\\\\
15\%=\frac{m_1}{ms_1}*100\%\\ms_1=10pints\\
15\%=\frac{m_1}{10}*100\%\\
\frac{15}{100}=\frac{m_1}{10}\ \ |*10\\
m_1=\frac{150}{100}=1,5pints\\\\
10\%=\frac{m_2}{15}*100\%\\
0,1=\frac{m_2}{15}\ \ |*15\\
1,5=m_2\\
Resulting\ solution:\\
ms=ms_1+ms_2=15+10=25pints\\m=m_1+m_2=1,5+1,5=3pints
\\\frac{m}{ms}*100\%=\frac{3}{25}*100\%=12\%
7 0
3 years ago
Manganese-56 is a beta emitter with a half-life of 2.6 hours. What is the mass of
Arisa [49]

Answer:

0.0009765625

Explanation: u just keep doing a half life till it goes to 13 aka

8.0g divided by 2  till you reach to 13 times of a half life ;p

8 0
3 years ago
Read 2 more answers
this element has an atomic number lower than that of aluminum and one less valence electrons then the Group 16 elements
ahrayia [7]
This element is nitrogen (N)
6 0
3 years ago
A sample initially contained 150 mg of radon-222. After 11.4 days only 18.75mg of the radon-222 in the sample remained. How many
beks73 [17]

<u>Answer: </u>

A sample initially contained 150 mg of radon-222. After 11.4 days only 18.75mg of the radon-222 in the sample remained where 3 half-lives have passed

<u>Explanation:</u>

Given, the initial value of the sample, A_0 = 150mg

Final value of the sample or the quantity left, A = 18.75mg

Time = 11.4 days

The amount left after first half life will be ½.

The number of half-life is calculated by the formula

\frac{A}{A_{0}}=\left(\frac{1}{2}\right)^{N}

where N is the no. of half life

Substituting the values,

\frac{18.75}{150}=\left(\frac{1}{2}\right)^{N}

\left(\frac{1}{2}\right)^{3}=\left(\frac{1}{2}\right)^{N}

On equating, we get, N = 3

Therefore, 3 half-lives have passed.

7 0
3 years ago
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