Answer:
The number of coils of wire around the core
Explanation:
A P E X approved✅
Explanation:
Steam evaporates as a gas into the air. even when you capture steam as it rises into the atmosphere, it can be turned back into h2o when cooled. because of evaporation, you will not get the same volume of water you started with.
<span>Mass of rock 1 is m1 = 10 kg Mass of rock 2 is m2 = 20 kg 10-kg rock takes T (the same time ) to reach the ground as similar to 20-kg rock that takes time T to reach the ground. If no air resistance is present, the rate of descent depends only on how far the object has fallen, no matter how heavy the object is. This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height. This statement follows from the law of conservation of energy and has been demonstrated experimentally by dropping a feather and a lead ball in an airless tube.
When air resistance plays a role, the shape of the object becomes important. THUS 10-KG & 20-KG ROCK reaches the ground in T-time</span>
Answer:
Explanation:
The magnitude of the electric force on this charged particle A depends upon the following
5. the distance between the point charge Q and the charged particle A
8. the amount of the charge on the point charge Q
9. the magnitude of charge on the charged particle A
Answer:
(6.67 × 10⁵) m/s
Explanation:
What will be the proton's speed a short time later when it reaches a point where the potential is -500V.
According to the law of comservation of energy, the sum of potential and kinetic energy of the proton at any point in time is always constant.
P.E₁ + K.E₁ = P.E₂ + K.E₂
P.E₁ = U₁ = qV₁
q = charge on the proton = (1.602 × 10⁻¹⁹) C
V₁ = 1500 V
P.E₁ = U₁ = (1.602 × 10⁻¹⁹) × (1500) = (2.403 × 10⁻¹⁶) J
K.E₁ = (1/2)mv₁²
m = mass of a proton = (1.673 × 10⁻²⁷) kg
v₁ = (2.5 × 10⁵) m/s
K.E₁ = (1/2)(1.673×10⁻²⁷)(2.5 × 10⁵)² = (5.23 × 10⁻¹⁷) J
P.E₂ = U₂ = qV₂
q = charge on the proton = (1.602 × 10⁻¹⁹) C
V₂ = -500 V
P.E₂ = U₂ = (1.602 × 10⁻¹⁹) × (-500) = (-8.01 × 10⁻¹⁷) J
K.E₂ = ?
P.E₁ + K.E₁ = P.E₂ + K.E₂
(2.403 × 10⁻¹⁶) + (5.23 × 10⁻¹⁷) = (-8.01 × 10⁻¹⁷) + K.E₂
K.E₂ = (2.403 × 10⁻¹⁶) + (5.23 × 10⁻¹⁷) + (8.01 × 10⁻¹⁷) = (3.727 × 10⁻¹⁶) J
K.E₂ = (1/2)mv₂²
m = (1.673 × 10⁻²⁷) kg
v₂ = ?
(3.727 × 10⁻¹⁶) = (1/2)(1.673 × 10⁻²⁷)v₂²
v₂² = (4.455 × 10¹¹)
v₂ = 667,457.863839 m/s = (6.67 × 10⁵) m/s
Hope this Helps!!!!
