Answer:
your right answer is true
hope it helps you
The answer:
<span>When the elevator accelerates upward at a rate of 3.6 m/s², the value of the acceleration becomes
</span>A=g+3.6=13.4 m/s²
and by using the newton's law, F=mass x A, we have
T1= (24 + 90 )x 13.4= 1527.6 N, where T1 is the <span>Tension in upper rope
</span> and
T2= ( 90 )x 13.4= 1206N, where T2 is the Tension in lower rope
When the elevator accelerates downward at a rate of 3.6 m/s², the value of the acceleration becomes
A=9.8 - 3.6 = 6.2 m/s²
T1= (24 + 90 )x 6.2= 706.8 N, where T1 is the Tension in upper rope
and
T2= ( 90 )x 6.2= 558N, where T2 is the Tension in lower rope
Answer:
Explanation:
Option C is the correct answer
Answer:
it was moving at 50m/s when it hits the well bottom
Explanation:
Using Newton first law of motion;
V=u+gt
v=final velocity (what we are about to calculate)
u=initial velocity which is 0
g= acceleration due to gravity 10m/s^2(since its expressing free fall it will be positive)
t=time taken 5seconds
v=0+10(5)
v=50m/s
