Answer:
Distance in pc= 20parsecs
Distance in zLY= 65.2LY
Distance in AU= 4.1×10^6AU
Explanation:
Using the formular:
d = 1/p
Where d = distance
P= parallax angle in arc of second
d= 1/0.050
d= 20 parsed
Converting to Lighy years,LY :
1 PC = 3.26LY
d= 20pc × (3.26Ly/1pc)
d= 65.2Ly
To convert to AU, 206,265 AU = 1pc
d= 20pc × (2.06×10^5AU/1pc)
d= 4.1×10^6AU
Answer:
B = 0.546 T, F = 2.59 10⁻¹² N
Explanation:
The magnetic force is
F = q v x B
We can calculate the magnitude of the force and find the direction by the right hand rule
F = q v B sin θ
Let's use Newton's second law
F = m a
Acceleration is centripetal
a = v² / r
We substitute
q v B sin θ = m v² / r
The angle between the field and the radius of the circle is 90º so sin 90 = 1
q B = m v / r
B = m v / q r
Let's calculate ’
B = 1.67 10⁻²⁷ 2.97 10⁷ / (1.60 10⁻¹⁹ 0.568)
B = 0.546 T
The foce is
F = q v B
F = 1.60 10⁻¹⁹ 2.97 10⁷ 0.546
F = 2.59 10⁻¹² N
Answer:
D)378kJ
Explanation:
Applying,
E = F×d................ Equation 1
Where E = Energy expanded by the car, F = Wind resistance, d = distance
From the question,
F = 0.42v²............ Equation 2
Susbtitute equation 2 into equation 1
E = 0.42v²d.............. Equation 3
Given: v = 30 m/s, d = 1 km = 1000 m
Substitute these values into equation 3
E = 0.42(30²)(1000)
E = 378000
E = 378 kJ
Hence the right option is D)378kJ
