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erica [24]
3 years ago
14

How much heat is required to increase the temperature of 1 kg of steel from 21 °C to 22 °C?

Physics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:

466J

Explanation:

Given parameters:

Mass of steel  = 1kg  = 1000g

Initial temperature  = 21°C

Final temperature  = 22°C

Unknown:

Amount of heat required for this temperature increase  = ?

Solution:

To solve this problem, we use the expression below:

  So;

Heat absorbed  = mass x specific heat of steel x change in temperature

Specific heat of steel  = 0.466J/g°C  

Therefore;

 Heat absorbed  = 1000 x 0.466 x (22  - 21)  = 466J

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Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric
Goshia [24]

Complete Question:

Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:

A. 2F

B. F/4

C. F/2

D. F

E. 4F

Answer:

D.

Explanation:

If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):

F =\frac{kQ*2Q}{r^{2} }

As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.

As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.

3 0
3 years ago
Which strategy should you use if your research question is too broad for the scope of your project? (1 O narrow the focus of res
Nesterboy [21]

Answer:

"Narrow the focus of research question"

Explanation:

O Narrow the focus of research question

    This is good! You can still use your question, but focus in on something so you have a proper research project.

O Add another research question

    Would adding another question to an already broad question help? No.

O Use the very first source you find for your project

    If your question is too broad, you should not use whatever you see first as it may be incorrect or does not answer the question

O Change the scope of your project​    

    You could, but if you have a set scope for your project (a) you might not be able to change it (b) you don't need to restart

Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0
2 years ago
Your friend provides a solution to the following problem. Evaluate her solution. The problem: Jim (mass 50 kg) steps off a ledge
Mekhanik [1.2K]

Answer:

No its wrong

Correct compression is 0.41

Explanation:

After jumping from 2m height on spring attached platform platform is compressed a distance x(let).

So work done by gravity on Jim is converted into spring potential energy.

k=8000 N/m

mass of Jim =50 kg

\frac{1}{2}k(x)^{2} =m*g(2+x)

\frac{1}{2}8000(x)^{2} =50*9.8(2+x)

8.16x^{2} =2 +x

Solve this quadratic one solution is positive and other is negative.

positive one is our answer = 0.41 m

5 0
3 years ago
According to the Theory of Continental Drift, what did the Earth’s continents look like 255 million years ago? What is the name
dmitriy555 [2]
The name of this landmas is known as <em></em>Pangaea, was a supercontinent that existed during the late Paleozoic and early Mesozoic eras. It formed approximately 300 million years ago and began to break apart after about 100 million years. 

Theres an image of how this supercontinet looked

3 0
3 years ago
Read 2 more answers
Two identical food packets were dropped from a helicopter. The first food packet was dropped from a height of 1,681 feet and the
Kazeer [188]

Answer:

The y intercept of the H2 is greater than H1.

Explanation:

Given,

The height from which the first food packet dropped = 1681 feet

The height from which the second food packet dropped = 961 feet

To find :

Two height functions and to compare in graph?

solution:

h1(t) = -16t^2 + 1681 is a vertical translation of h2(t) = -16t^2 + 961.

The y-intercept of h2 is 720 ft less than that of h1.

h1(t) = -4t^2 + 41 is a vertical translation of h2(t) = -4t^2 + 31.

The y-intercept of h2 is 10 ft greater than that of h1.

h1(t) = -16t^2 + 1681 is a vertical translation of h2(t) = -16t^2 + 961.

The y-intercept of h2 is 720 ft greater than that of h1.

h1(t) = -4t^2 + 41 is a vertical translation ofh2(t) = -16t^2 + 31.

The y-intercept of h2 is 10 ft less than that of h1.

3 0
3 years ago
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