A car starts from rest and accelerates at 2.5m/s^2 for 2s. What is the final velocity of the car
1 answer:
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Explanation:
power = Force × distance /time
power = 944N × 12.4m/36secs
power = (944×12.4/36)Nms—¹
power = 390.2Nms—¹ or 390.2Watts or 390.2Js—¹
Answer:
u = 13.67 m/s
Explanation:
given,
window height = 2 m
window is 7.5 m off the ground on its path up
total distance from the ground to pass the window = 2 + 7.5 = 9.5 m
time taken to go past the window = 1.30 s
using equation of motion
u = 13.67 m/s
hence, the initial velocity of the ball is equal to 13.67 m/s