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umka2103 [35]
3 years ago
10

Which law states that the pressure and absolute temperature of a fixed quantity of gas ate directly proportional under constant

volume conditions
Chemistry
1 answer:
belka [17]3 years ago
4 0
The correct answer is Charle's law. This law law states that the pressure and absolute temperature of a fixed quantity of gas ate directly proportional under constant volume conditions. It is expressed as V/T = C where is some constant that is constant for all conditions given that pressure is constant.
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What is the chemical symbol for fluorine?
NeX [460]

The chemical symbol is F

8 0
3 years ago
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How much pressure does an elephant with a mass of 2200 Kg and a total footprint area of 4500 cm2 exert on the ground?
Debora [2.8K]

Answer:

47911.1 pa

Explanation:

The SI base unit of pressure is pascal, which is N/m^2.

2200 kg is 2200*9.8=21560 N, and 4500 cm^2=4500/10000=0.45 m^2.

So the total pressure exerted on the ground (!!) is 21560/0.45= 47911.1 Pa.

6 0
3 years ago
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PLEASE HELP FOR THIS ASSIGNMENT
mars1129 [50]
<h2>Steps:</h2>
  • Remember that Density = mass/volume, or D = m/v

So firstly, we have to find the volume of the rock. To do this, we need to subtract the volume of water A from the volume of the water B. In this case:

  • Water A = 30 mL
  • Water B = 40 mL
  • 40 mL - 30 mL = 10 mL

<u>The volume of the rock is 10 mL.</u>

Now that we have the volume, we can plug that and the density of the rock into the density equation to solve for the mass.

3.678=\frac{m}{10}

For this, multiply both sides by 10:

36.78=m

<h2>Answer:</h2>

<u>Rounding to the tenths place, the mass of the rock is 36.8 g, or C.</u>

6 0
4 years ago
Calculate how many grams of oxygen form when 2.72 g of KCIOg reacts completely given the
34kurt

1.06g

Please refer to the image attached.

You first find the number of moles (n) for KClO3 as you have been given the mass. So n = mass/Mr gives you the moles that is 0.022 mol

Next you use the ratio 2:3 as per the equation where it's 2KClO3 ---> 3O2 so you just cross multiply and get the moles for oxygen.

Now that you know the number of moles for oxygen, you can use the same moles equation that you used earlier to find the mass. mass=n×Mr and so you get the answer as 1.06g of oxygen.

4 0
3 years ago
10-kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the con
Mariulka [41]

Answer:

Temperature = 0.605°C

Total enthalpy at 300kpa = 545.2 kJ

Total enthalpy at 600kpa = 846.45 kJ.

Explanation:

Checking the table for 134a pressure table. It is given that the specific volume of saturated liquid and the specific volume of the saturated vapor of 280kpa is 0.0007699 m^3/kg and 0.072352 m^3/kg respectively.

Also, the specific volume of saturated liquid and the specific volume of the saturated vapor of 320kpa is 0.0007772 m^3/kg and 0.063604 m^3/kg respectively.

The first thing to do is to determine the value for the specific volume of saturated liquid.

At 300 kpa, the specific volume of saturated liquid,n is given below as;

300 - 280/ 320 - 280 = (n - 0.0007699)/ 0.0007772 - 0.0007699.

Therefore, n = specific volume of saturated liquid = 0.0007735 m^3/kg.

300 - 280/ 320 - 280 = n - 0.072352/ (0.063604 - 0.072352).

n = 0.0679 m^3/kg.

The second thing to do is to determine the value of the specific volume.

Specific volume = 14 × 10^-3/ 10 = 0.0014 m^3/kg.

Determine the enthalpy of the mixture,b(I). This is given below as;

300 - 280/ 320 - 280 = b(I) - 199.54/ (196.7 - 199.54).

b(I) = 198.125 kJ/Kg.

Hence, b = [ 300 - 280/ 320 - 280 = j - 50.18 / 55.16 - 50.18] + [ ( 0.0014 - 0.00077735) / 0.067978 - 0.00077735] × 198.125.

b = 54.517 KJ/Kg.

Total enthalpy = 10 × 54.517 = 545.17 kJ.

Temperature can be Determine as below;

300 - 280/ 320 - 280 = T + 1.25 / 2.46 - 1.25.

Temperature = 0.605°C.

Hence, at 600kpa, the total enthalpy = [81.51 + ( 0.0014 - 0.0008199/ 0.034295 - 0.0008199) × 180.90] × 10

Total enthalpy at 600kpa = 846.45 kJ.

3 0
3 years ago
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