Hey the answer to the question is
m = 0.40
Answer:
W = 166422.729 N
Explanation:
given,
diameter of the balloon = 30 m
density of the air = 1.10 Kg/m³
weight of the balloon and cargo = ?
density of the surrounding air = 1.20 kg/m³
we know,
Density = mass/volume
m = density x volume
m = 16964.6 Kg
Weight of the balloon
W = m g
W = 16964.6 x 9.81
W = 166422.729 N
Weight of the balloon and the cargo is equal to W = 166422.729 N
Answer:
ΔΦ = -3.39*10^-6
Explanation:
Given:-
- The given magnetic field strength B = 0.50 gauss
- The angle between earth magnetic field and garage floor ∅ = 20 °
- The loop is rotated by 90 degree.
- The radius of the coil r = 19 cm
Find:
calculate the change in the magnetic flux δφb, in wb, through one of the loops of the coil during the rotation.
Solution:
- The change on flux ΔΦ occurs due to change in angle θ of earth's magnetic field B and the normal to circular coil.
- The strength of magnetic field B and the are of the loop A remains constant. So we have:
Φ = B*A*cos(θ)
ΔΦ = B*A*( cos(θ_1) - cos(θ_2) )
- The initial angle θ_1 between the normal to the coil and B was:
θ_1 = 90° - ∅
θ_1 = 90° - 20° = 70°
The angle θ_2 after rotation between the normal to the coil and B was:
θ_2 = ∅
θ_2 = 20°
- Hence, the change in flux can be calculated:
ΔΦ = 0.5*10^-4*π*0.19*( cos(70) - cos(20) )
ΔΦ = -3.39*10^-6
