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salantis [7]
3 years ago
10

A. Group of cross country runners decided to go on an hour and a half run. During the first hour, they ran a total of 13 kilomet

ers. Then, they ran 5.0 kilometers during the next half an hour. What was the group's average speed for the entire run?
Physics
1 answer:
pshichka [43]3 years ago
3 0

Answer:

The average speed for the entire run is 12 km/h.

Explanation:      

The average speed is given by the following equation:

\overline{v} = \frac{d_{T}}{t_{T}}

Where:

d_{T}: is the total distance

t_{T}: is the total time

If during the first hour, they ran a total of 13 kilometers and then, they ran 5.0 kilometers during the next half an hour we have:

d_{T} = 13 km + 5 km = 18 km

t_{T} = 1 h + \frac{1}{2} h = 1.5 h

Hence, the average speed is:

\overline{v} = \frac{d_{T}}{t_{T}} = \frac{18 km}{1.5 h} = 12 km/h

Therefore, the average speed for the entire run is 12 km/h.

I hope it helps you!                                                                                      

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Ammonia gas occupies a volume of 0.450 L at a pressure of 96 kPa. What
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Answer:

0.426 L

Explanation:

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Given information

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Two long, parallel, current-carrying wires lie in an xy-plane. The first wire lies on the line y = 0.300 m and carries a current
Marrrta [24]

Answer:

Explanation:

Since the wires attract each other , the direction of current will be same in both the wires .

Let I be current in wire which is along x - axis

force of attraction per unit length between the two current carrying wire is given by

\frac{\mu_0}{4\pi}  x \frac{2 I_1\times I_2}{d}

where I₁ and I₂ are currents in the wires and d is distance between the two

Putting the given values

285 x 10⁻⁶ = 10⁻⁷ x \frac{2\times25.5\times I_2}{.3}

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Current in the wire along x axis is 16.76 A

To find point where magnetic field is zero due the these wires

The point will lie between the two wires  as current is in the same direction.

Let at y = y , the neutral point lies

k 2 x  \frac{16.76}{y} = k 2 x \frac{25.5}{.3-y}

25.5y = 16.76 x .3 - 16.76y

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