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tamaranim1 [39]
3 years ago
11

Determine the amount in grams of KCl that exists in 20.3 g of a solution that contains 1.14 % KCl by mass 1.14 g KCl

Chemistry
1 answer:
Fiesta28 [93]3 years ago
3 0

The mass of KCl that exists in 20.3 g of solution containing 1.14% by mass of KCl is 0.23 g

From the question given above, the following data were obtained:

Mass of solution = 20.3 g

Percentage of KCl = 1.14% = 1.14 / 100 = 0.0114

<h3>Mass of KCl =?</h3>

Percentage = \frac{mass of solute}{mass of solution}   * 100\\\\0.0114 = \frac{mass of KCl}{20.3} \\\\

Cross multiply

Mass of KCl = 0.0114 × 20.3

<h3>Mass of KCl = 0.23 g</h3>

Therefore, the mass of KCl in the solution is 0.23 g

Learn more: brainly.com/question/14876861

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Answer:

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Explanation:

CU2O has 2 coefficient

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One container is filled with argon gas and the other with krypton gas. If both gases have the same temperature, in which contain
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Answer:

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Explanation:

The average kinetic energy of the particles in a gas is given by

KE=\frac{1}{2}mv^2

where

m is the mass of the particles

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The average kinetic energy of the particles in a gas can also be written as

KE=\frac{3}{2}kT

where

k is the Boltzmann's constant

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Combining the two equations,

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We can re-write the equation as

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Therefore, if the two gases are at same temperature, the particles will move faster in the gas with lighter particles (smaller mass).

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