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3 years ago

Determine the amount in grams of KCl that exists in 20.3 g of a solution that contains 1.14 % KCl by mass 1.14 g KCl

Chemistry

1 answer:

Fiesta28 [93]3 years ago

3 0

The mass of KCl that exists in 20.3 g of solution containing 1.14% by mass of KCl is 0.23 g

From the question given above, the following data were obtained:

Mass of solution = 20.3 g

Percentage of KCl = 1.14% = 1.14 / 100 = 0.0114

$Percentage = \frac{mass of solute}{mass of solution} * 100\\\\0.0114 = \frac{mass of KCl}{20.3} \\\\$

Cross multiply

Mass of KCl = 0.0114 × 20.3

Therefore, the mass of KCl in the solution is 0.23 g

Learn more: brainly.com/question/14876861

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