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2 years ago

Determine the amount in grams of KCl that exists in 20.3 g of a solution that contains 1.14 % KCl by mass 1.14 g KCl

Chemistry

1 answer:

Fiesta28 [93]2 years ago

3 0

The mass of KCl that exists in 20.3 g of solution containing 1.14% by mass of KCl is 0.23 g

From the question given above, the following data were obtained:

Mass of solution = 20.3 g

Percentage of KCl = 1.14% = 1.14 / 100 = 0.0114

$Percentage = \frac{mass of solute}{mass of solution} * 100\\\\0.0114 = \frac{mass of KCl}{20.3} \\\\$

Cross multiply

Mass of KCl = 0.0114 × 20.3

Therefore, the mass of KCl in the solution is 0.23 g

Learn more: brainly.com/question/14876861

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2 years ago

Read 2 more answers

Write the symbol for each of the following ions:

kap26 [50]

Answer:

a) $_{31}^{71}\textrm {P^{3+}}$

b) $_{35}^{80}\textrm {Br^{-}}$

c) $_{90}^{232}\textrm {Th^{4+}}$

d) $_{38}^{87}\textrm {Sr^{2+}}$

Explanation:

For neutral atoms:

Atomic Number (Z)= number of protons = number of electrons

Mass number (A) = number of protons + number of neutrons

For ions with positive net charge:

Number of protons = Z + net charge

For ions with negative net charge:

Number of protons= Z - net charge

a) A = 71, Charge = +3

Number of electrons = 28

Number of protons = 28 +3 =31

$_{31}^{71}\textrm {P^{3+}}$

b) A = 35, Z = 45+35=80, Charge = -1

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Number of neutrons = 45

Number of electrons = 36

Charge = Number of protons- Number of electrons =35-36 = -1

$_{35}^{80}\textrm {Br^{-}}$

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Number of electrons = 86

Number of protons = Z = 86+4 = 90

mass number = A = 90+142 = 232

$_{90}^{232}\textrm {Th^{4+}}$

d) Charge = +2

Atomic number = Number of protons = Z = 38

mass number = A = 87

$_{38}^{87}\textrm {Sr^{2+}}$

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