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tamaranim1 [39]
3 years ago
9

64 g of sulfur dioxide (SO2) contains 32 g of oxygen. Calculate how much sulfur it contains.

Chemistry
1 answer:
Contact [7]3 years ago
8 0

Answer:

32 grams

Explanation:

64 g SO2 - 32g O2= 32g S

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For every 1 mole of C6H12O6, you need 6 moles of water. Multiply the 2.5 moles you are trying to make by the 6 of water you need, and 4) 15 is your answer.
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Bromine gas in a container is heated over a flame. What happens to the average kinetic energy of the bromine particles? It decre
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Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb ( NO 3 ) 2
nikklg [1K]

Answer : The volume of NH_4I solution required is, 2.93 L

The number of moles of PbI_2 formed from the reaction is, 0.662 moles.

Explanation :

First we have to calculate the initial moles of Pb(NO_3)_2.

\text{Moles of }Pb(NO_3)_2=\text{Concentration of }Pb(NO_3)_2\times \text{Volume of solution}

\text{Moles of }Pb(NO_3)_2=0.700M\times 0.945L=0.662mol

Now we have to calculate the moles of NH_4I

The balanced chemical reaction is:

Pb(NO_3)_2(aq)+2NH_4I(aq)\rightarrow PbI_2(s)+2NH_4NO_3(aq)

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react with 2 moles of NH_4I

So, 0.662 mole of Pb(NO_3)_2 react with 0.662\times 2=1.32 moles of NH_4I

Now we have to calculate the volume of NH_4I

\text{Volume of }NH_4I=\frac{\text{Moles of }NH_4I}{\text{Concentration of }NH_4I}

\text{Volume of }NH_4I=\frac{1.32mol}{0.450mol/L}=2.93L

Now we have to calculate the moles of PbI_2

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react to give 1 moles of PbI_2

So, 0.662 mole of Pb(NO_3)_2 react to give 0.662 moles of PbI_2

Thus, the number of moles of PbI_2 formed from the reaction is, 0.662 moles.

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3 years ago
Write a balanced chemical equation for the standard formation reaction of solid chromium(iii) nitrate crno33 .
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Explanation:

Standard formation of an substance is defined as formation of one mole of substance from its constituting elements.

Chromium(III) nitrate is composed of chromium, nitrogen and three oxygen atoms.

2Cr(s)+3N_2(g)+9O_2\rightarrow 2Cr(NO_3)_3(s)

A balanced chemical equation for the standard formation reaction of solid chromium(III) nitrate

Cr(s)+\frac{3}{2}N_2(g)+\frac{9}{2}O_2\rightarrow Cr(NO_3)_3(s)

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