Answer:
A. the wave speed v and Wavelength
Explanation:
Given that
Mass density per unit length=μ
Frequency = f
The velocity V given as


T=Tension
V=Velocity
V= f λ
λ=Wavelength
Therefore to find the tension ,only wavelength and speed is required.
The answer is A.
<h2>
Energy used by heater is 8.21 x 10⁶ J</h2>
Explanation:
Energy = Power x Time
Power = Voltage x Current
Voltage = 120 V
Current = 9.5 A
Power = Voltage x Current
Power = 120 x 9.5 = 1140 W
Time = 2 hours = 2 x 60 x 60 = 7200 s
Energy = Power x Time
Energy = 1140 x 7200
Energy = 8208000 J
Energy used by heater is 8.21 x 10⁶ J
The answer for that would be C
Answer:
(A) Consists of a small number of tiny particles that are far apart- relative in their size.
Explanation:
An <em>ideal gas</em> is defined as a simplification of a real gas, with punctual particles, in which all collisions are elastic, with random displacements and with no attractive force between them.
The assumption of the particles being punctual make clear that they do not have size at all. So if they were far apart-relative in their size, they can not collide each other, that is why assumption (B) can not be possible (<u><em>for that particular case</em></u>).
It is clear that (A) is not an assumption for an ideal gas, because do not fit in any of its properties.
Elastic collision: It is a case in which the energy is conserved (Kinetic Energy).
Kinetic Energy: It is the energy that will have an object as a consequence of its movement.
Answer:
A. 1.64 J
Explanation:
First of all, we need to find how many moles correspond to 1.4 mg of mercury. We have:

where
n is the number of moles
m = 1.4 mg = 0.0014 g is the mass of mercury
Mm = 200.6 g/mol is the molar mass of mercury
Substituting, we find

Now we have to find the number of atoms contained in this sample of mercury, which is given by:

where
n is the number of moles
is the Avogadro number
Substituting,
atoms
The energy emitted by each atom (the energy of one photon) is

where
h is the Planck constant
c is the speed of light
is the wavelength
Substituting,

And so, the total energy emitted by the sample is
