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Monica [59]
3 years ago
9

Why are metals generally good conductors of electric current?

Chemistry
1 answer:
lakkis [162]3 years ago
8 0

Answer:

(Hope this helps can I pls have brainlist (crown)☺️)

Explanation:

Because the atoms in metals form a matrix through which outside electrons may easily travel, metals are good conductors of electricity and heat. They generate a sea of electrons around the positive nuclei of the interacting metal ions, rather than circling their particular atoms.

The free flow of shared electrons can carry an electric current through a metal. Carbon atoms join with iron atoms to create bonds.

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Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an
garri49 [273]

Explanation:

The given data is as follows.

      T = 120^{o}C = (120 + 273.15)K = 393.15 K,  

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So,            x_{1} = 0.5   and   x_{2} = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

               p^{sat}_{1} (393.15 K) = 9.2 bar

               p^{sat}_{1} (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

                 p_{1} = x_{1} \times p^{sat}_{1}

                            = 0.5 \times 9.2 bar

                             = 4.6 bar

and,           p_{2} = x_{2} \times p^{sat}_{2}

                         = 0.5 \times 10.5 bar

                         = 5.25 bar

Therefore, the bubble pressure will be as follows.

                           P = p_{1} + p_{2}            

                              = 4.6 bar + 5.25 bar

                              = 9.85 bar

Now, we will calculate the vapor composition as follows.

                      y_{1} = \frac{p_{1}}{p}

                                = \frac{4.6}{9.85}

                                = 0.467

and,                y_{2} = \frac{p_{2}}{p}

                                = \frac{5.25}{9.85}

                                = 0.527  

Calculate the dew point as follows.

                     y_{1} = 0.5,      y_{2} = 0.5  

          \frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}

           \frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}

             \frac{1}{P} = 0.101966 bar^{-1}              

                             P = 9.807

Composition of the liquid phase is x_{i} and its formula is as follows.

                   x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{9.2}

                               = 0.5329

                    x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{10.5}

                               = 0.467

4 0
4 years ago
Which of the following pairs of reactants is not correctly listed with its product solution? A. Strong base-strong acid reactant
alexandr1967 [171]

Answer: Option B

Explanation: when strong acid react with strong base, the resulting solution is neutral as in the case of HCl and NaOH

HCl + NaOH —> NaCl + H2O

From the equation obtained, The salt ( NaCl) obtained is a normal salt which is neutral.

4 0
3 years ago
Which of the following are examples of physical change? Copper oxidizing Iron rusting Carbon dioxide sublimating Water evaporati
kari74 [83]
Carbon dioxide sublimation
water evaporate

physical change is just change between solid/liquid/gas, other two are chemical changes
6 0
3 years ago
A gas occupies a volume of 40.0 milliliters at 20 c if the volume is increased too 80.0 milliliters at constant pressure, the re
Troyanec [42]
Charles law gives the relationship between temperature and volume of gases. It  states that the volume of gas is directly proportional to temperature at constant pressure. 
V / T = k 
where V - volume and T - temperature in Kelvin and k - constant 
\frac{V1}{T1} =  \frac{V2}{T2}
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
T1 - 20 °C + 273 = 293 K
substituting these values in the equation 
\frac{40.0 mL}{293 K}  =  \frac{80.0 mL}{T}
T = 586 K
temperature in celsius = 586 K - 273 = 313 °C
new temperature is 313 °C
8 0
4 years ago
Where in the laboratory is long, unrestrained hair most likely to be a safety concern? near an open flame close to a fume hood n
zimovet [89]

Answer:

near an open flame

Explanation:

if your hair is not tied back near open flames in combination with most hair care products it would turn you into a living torch

7 0
3 years ago
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