The Tangent Line Problem 1/3How do you find the slope of the tangent line to a function at a point Q when you only have that one point? This Demonstration shows that a secant line can be used to approximate the tangent line. The secant line PQ connects the point of tangency to another point P on the graph of the function. As the distance between the two points decreases, the secant line becomes closer to the tangent line.
ANSWER
The simplest form of the ratio

is

EXPLANATION
The ratio given to us is

We can divide each term in ratio by the same number.
To find the ratio in the simplest form we divide the terms in the ratio by their highest common factor, which is

This implies that,

We simplify this to obtain,

The correct answer is C.
Alternatively,


This implies that,
Given:
bottom of the plank or ground is 9 feet from the wall
length of the plant is 41 ft
height of the wall is unknown.
Let us use the Pythagorean theorem.
a² + b² = c²
a² + (9ft)² = (41ft)²
a² + 81 ft² = 1,681 ft²
a² = 1,681 ft² - 81 ft²
a² = 1,600 ft²
√a² = √1,600 ft²
a = 40 ft
The height of the wall is 40 ft.
Answer:
3(n+5)=-30
Step-by-step explanation:
Three times the sum of a number and 5 is - 30
Vocabulary:
times = multiplication, represented with *
sum = addition, represented by +
unknown number = n
Three * the sum of a number and 5
The sum of a number and 5 is the same as saying n + 5
So we are multiplying 3 by n + 5
Because n is an unknown variable we have to separate the sum of n and 5 from being multiplied by 3 with parenthesis. We do this because if we want to multiply 3 by the sum of n and 5. If we put 3 * n + 5 we are only multiplying the unknown variable by 3 not including the 5 that is added to it.
So we get 3( n + 5 ) is -30
3(n+5)=-30 is the answer.
My key can’t perform this but I can solve it on a sheet...
So here I really hopes this helps