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Anit [1.1K]
3 years ago
14

The anion O3− does not obey the octet rule. Draw its Lewis structure and state the type of octet-rule exception. Indicate the va

lues of nonzero formal charges and include lone pair electrons.
Chemistry
1 answer:
Tju [1.3M]3 years ago
3 0

One of the oxygen atoms in the anion O3− is hypervalent and the formal charge on this oxygen atom is -1.

Ozone is a triatomic molecule. The anion formed from ozone is called the ozonide anion. This anion is also triatomic. The resonance structures of the ozonide anion are shown in the image attached to this answer.

We can see that one of the oxygen atoms in the ozonide ion is hypervalent because it contains ten instead of eight electrons. This hypervalent oxygen atom has a formal charge of -1 while the two other oxygen atoms has a formal charge of zero.

Learn more: brainly.com/question/8646601

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Entropy -

In a system, the randomness is measured by the term entropy .

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From the question ,

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Reactant - 1 + 5 = 6

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Hence ,

More number of gaseous atoms are present in the product side , So ,

entropy will increase , i.e. Δ°S > 0

( b ) CH₄(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(g)

Gaseous atoms -

Reactant - 1 + 2 = 3

Product - 1 + 2 = 3 ,

Since ,

Both the side the value of gaseous atoms are , hence , Δ°S = 0 .

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Gaseous atoms -

Reactant = 0

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Since ,

Hence ,

More number of gaseous atoms are present in the product side , So ,

entropy will increase , i.e. Δ°S > 0

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