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Hoochie [10]
3 years ago
13

if 2.4l of chlorine at 400 mm hg are compressed to 725 mm hg at a constant temperature. what is the new volume?

Chemistry
1 answer:
Ksivusya [100]3 years ago
3 0

Answer: 1.324L

Explanation: use Boyles law, sorry so late!

You might be interested in
Sodium bicarbonate is sometimes used to neutralize acid spills. If 2.0 L of 1.0 M H2SO4 is spilled, what mass of sodium bicarbon
UkoKoshka [18]

Answer:

168.0 g

Explanation:

First thing, write a balanced chemical equation:

H_{2}SO_{4}+ 2NaHCO_{3}  ----> Na_{2}SO_{4} + 2H_{2}O+2CO_{2}

n(H2SO4) = concentration * volume

                = 1.0 M * 2.0 L

                = 2.0 mol

According to the balanced equation, 1 mol of acid requires 2 mol of sodium bicarbonate. This means that 2 mol of acid requires 2 mol of sodium bicarbonate. What mass of sodium bicarbonate is this?

mass (NaHCO3) = number of moles * molar mass

                           = 2.0 mol * 84.0065 g/mol

                           = 168.0 g

4 0
3 years ago
What are the charges of carbon when in bonds, please give detail
asambeis [7]
Carbon can go either way they can have a 4+ charge (by losing 4 electrons) or a 4- charge (by gaining 4 electrons) to fulfill the octet rule.
4 0
4 years ago
How many grams of C are in 500g or NaHCO3​
harina [27]

Answer: 71.43g

Explanation: The RMM of NaHCO3 is

23+1+12+16(3)=84.

There is one carbon in NaHCO3 thus there are 1×12g of C in NaHCO3.

Thus

85gNaHCO3-----12g C

500gNaHCO3---- xgram

(500×12)÷84= 71.43

7 0
3 years ago
The first evidence supporting the theory of continental drift was ____.
Elina [12.6K]
<span>The first evidence supporting the theory of continental drift was the fitting together of neighboring continents like jigsaw puzzle pieces.




Do you need an explanation? </span>
4 0
4 years ago
Read 2 more answers
A) The lab tech called in sick today and you are called in to help prepare
jarptica [38.1K]
<h3>Answer:</h3>

318.405 g

<h3>Explanation:</h3>

We are given;

  • Volume of K₃PO₄ solution to be prepared as 750.0 mL or 0.75 L
  • Molarity of the solution to be prepared as 2.00 M

We are required to determine the mass of K₃PO₄ to be measured.

<h3>Step 1: Determine the number of moles of K₃PO₄</h3>

Molarity = Moles ÷ Volume

Rearranging the formula;

Number of moles = Molarity × Volume

Therefore;

Moles of K₃PO₄ = 2.00 M × 0.75 L

                          = 1.5 moles

<h3>Step 2: Determine the mass of K₃PO₄ to be measured</h3>

Mass = Number of moles × Molar mass

Molar mass of K₃PO₄ = 212.27 g/mol

Therefore;

Mass of K₃PO₄ = 1.5 moles × 212.27 g/mol

                        = 318.405 g

Therefore, the mass of K₃PO₄ that should be weighed is 318.405 g

7 0
3 years ago
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