MULTIPLE CHOICE What is the molality (m) of 3.5 mol of sugar in 2.5 kg of water?
1 answer:
The molality of the solution is 1.4 moles per kilogram (molal).
The molality of the solution is equal to the number of moles of sugar (solute) divided by the number of kilograms of water (solvent). Hence, the molality is determined below:
The molality of the solution is 1.4 moles per kilogram (molal).
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Answer:
a) [H₃O⁺] = 1.8x10⁻⁵ M
b) pH = 4.75
c) % rxn = 3.5x10⁻³ %
Explanation:
a) The dissociation reaction of HCN is:
HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)
0.5 M - x x x
The dissociation constant from the above reactions is given by:
By solving the above quadratic equation we have:
x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]
Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.
b) The pH is equal to:
Then, the pH of the HCN solution is 4.75.
c) The % reaction is the % ionization:
Therefore, the % reaction or % ionization is 3.5x10⁻³ %.
I hope it helps you!
Energy given by carbohydrates present in one cup = = 128 kcal
Energy given by proteins present in one cup =
Energy given by fat in one cup =
Total energy in one cup of cereal box = 128 kcal + 16 kcal + 18 kcal = 162 kcal
Energy present in two cups = [tex] 2 cups * \frac{162 kcal}{1 cup} *
= 324 kcal