Question

MULTIPLE CHOICE What is the molality (m) of 3.5 mol of sugar in 2.5 kg of water?

Answer 1

The molality of the solution is 1.4 moles per kilogram (molal).

The molality of the solution is equal to the number of moles of sugar (solute) divided by the number of kilograms of water (solvent). Hence, the molality is determined below:

$m = \frac{3.5\,mol}{2.5\,kg}$

$m = 1.4\,\frac{mol}{kg}$

The molality of the solution is 1.4 moles per kilogram (molal).

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