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3 years ago

How to determine is an alcohol has strong or weak intermolecular forces?

Chemistry

1 answer:

Mashcka [7]3 years ago

5 0

Yes its due to dipole force which is able to reach in closer called the hydrogen bonding

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Iron(III) oxide is formed when iron combines with oxygen in the air.

Alisiya [41]

Answer:

Mass = 9.58 g

Explanation:

Given data:

Mass of Fe₂O₃ formed = ?

Mass of Fe = 6.7 g

Solution:

Chemical equation:

4Fe + 3O₂ → 2Fe₂O₃

Number of moles of Fe:

Number of moles = mass/molar mass

Number of moles = 6.7 g/ 55.8 g/mol

Number of moles = 0.12 mol

now we will compare the moles of Fe and Fe₂O₃.

Fe : Fe₂O₃

4 : 2

0.12 : 2/4×0.12 = 0.06 mol

Mass of Fe₂O₃:

Mass = number of moles × molar mass

Mass = 0.06 mol × 159.69 g/mol

Mass = 9.58 g

8 0

3 years ago

(3.6 x 104) / (4 x 10-6)

Feliz [49]

Answer:

930 pls mark me branilest

4 0

2 years ago

Read 2 more answers

What is the volume of 3.2 moles of chlorine gas (Cl2) at 295 K and 1.1 atm?

Lostsunrise [7]

Answer:

$\boxed{\text{70 L}}$

Explanation:

We can use the Ideal Gas Law to solve this problem

pV = nRT

Data:

p = 1.1 atm

n = 3.2 mol

R = 0.082 16 L·atm·K⁻¹mol⁻¹

T = 295 K

Calculation:

$\begin{array}{rcl}1.1V\text{ atm} & = & \text{3.2 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{295 K}\\1.1V & = & \text{77.5 L}\\\\V & = &\dfrac {\text{77.5 L}}{1.1}\\\\V & = & \text{70 L}\\\end{array}\\\text{The volume is }\boxed{\textbf{70 L}}$

3 0

3 years ago

NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

tresset_1 [31]

convection and conduction, but not radiation

4 0

3 years ago

Read 2 more answers

It takes 38 mL of 0.75 M NaOH solution to completely neutralize 155 mL of a sulfuricacid solution (H2SO4). a.Write a balanced eq

AnnyKZ [126]

Answer:

a. $H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

b. 0.092 M

Explanation:

Hello!

In this case, since for this titration process we know the used volume of 0.75-M sodium hydroxide needed to neutralize 155 mL of the acid, we first need to write the undergoing chemical reaction between them:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

This, since there is 1:2 mole ratio between the acid and the base, at the equivalent point we must respect:

$2*n_{acid}=n_{base}$

That in terms of concentrations and volumes is:

$2*M_{acid}V_{acid}=M_{base}V_{base}$

Thus, the concentration of acid was:

$M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}} \\\\M_{acid}=\frac{0.75M*38mL}{2*155mL} \\\\M_{acid}=0.092M$

Best regards!

4 0

3 years ago