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2 years ago

1. If a Gear with a 3 inch Diameter is being turned by a Gear with a 6 inch Diameter, which Gear will rotate at a higher Rate?

Engineering

1 answer:

pshichka [43]2 years ago

5 0

Answer:

The smaller gear will rotate faster.

Explanation:

If a larger gear is driven by a smaller gear, the large gear will rotate slower than the smaller gear but will have a greater moment. For example, a low gear on a bike or car. If a smaller gear is driven by a larger gear, the smaller gear will rotate quicker than the larger gear but will have a smaller moment.

I hope this helps! :)

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How can any student outside apply for studying engineering at Cambridge University

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2 years ago

Another focus of effective communication, according to Stephen Covey, is ensuring that:

svetoff [14.1K]

Answer:

Stephen Covey believes this principle is the key to effective interpersonal communication. Seek first to understand, then to be understood. This habit is about communicating with others. It's about developing the habit of listening carefully and really understanding the other person BEFORE giving your thoughts.

Explanation:

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2 years ago

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Which of the following is not a function of the cooling system

Pie

Answer:

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Explanation:

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1 year ago

Two substances, A and B, initially at different temperatures, come into contact and reach thermal equilibrium. The mass of subst

Kaylis [27]

Answer:

The specific heat capacity of substance A is 1.16 J/g

Explanation:

The substances A and B come to a thermal equilibrium, therefore, the heat given by the hotter substance B is absorbed by the colder substance A.

The equation becomes:

Heat release by Substance B = Heat Gained by Substance A

The heat can be calculated by the formula:

Heat = mCΔT

where,

m = mass of substance

C = specific heat capacity of substance

ΔT = difference in temperature of substance

Therefore, the equation becomes:

(mCΔT) of A = (mCΔT) of B

FOR SUBSTANCE A:

m = 6.01 g

ΔT = Final Temperature - Initial Temperature

ΔT = 46.1°C - 20°C = 26.1°C

C = ?

FOR SUBSTANCE B:

m = 25.6 g

ΔT = Initial Temperature - Final Temperature

ΔT = 52.2°C - 46.1°C = 6.1°C

C = 1.17 J/g

Therefore, eqn becomes:

(6.01 g)(C)(26.1°C) = (25.6 g)(1.17 J/g)(6.1°C)

C = (182.7072 J °C)/(156.861 g °C)

C = 1.16 J/g

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2 years ago

Ben İngiliz oldum düzelte bilirmiyim

Lelu [443]

Answer:

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Explanation:

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2 years ago