Answer:
The distance between the station A and B will be:
Explanation:
Let's find the distance that the train traveled during 60 seconds.
We know that starts from rest (v(0)=0) and the acceleration is 0.6 m/s², so the distance will be:


Now, we need to find the distance after 25 min at a constant speed. To get it, we need to find the speed at the end of the first distance.


Then the second distance will be:

The final distance is calculated whit the decelerate value:

The final velocity is zero because it rests at station B. The initial velocity will be v(1).


Therefore, the distance between the station A and B will be:
I hope it helps you!
No clue sorry man I would help but I need help too
Answer: answer provided in the explanation section.
Explanation:
Weather phenomenons that would impart Aviation Operations in Santa Barbara -
1. Although winters are cold, wet, and partly cloudy here. It is in general favorable for flying. But sometimes strong winds damage this pleasant weather.
2. The Sundowner winds cause rapid warming and a decrease in relative humidity. The wind speed is very high surrounding this area for this type of wind.
3. Cloud is an important factor that affects aviation operations. Starting from April, here the sky is clouded up to November. The sky is overcast (80 to 100 percent cloud cover) or mostly cloudy (60 to 80 percent) 44% on a yearly basis. Thus extra cloud cover can trouble aviation operations.
4. The average hourly wind speed can also be a factor. This also experiences seasonal variations, these variations are studied carefully in the aviation industry. The windier part of the year starts in January and ends in June. In April, the wind speed can reach 9.5 miles per hour.
This and more are some factors to look into when considering wheather conditions that would affect aviation operations.
I hope this was a bit helpful. cheers
The speed of the car A is 6.05 m/s and the speed of the car B just after the collision 7.65 m/s.
Ma=15 mg , Mb=25mg
Vai=5 m/s vbi=7 m/s
We know coeffecient of restitution
e=|Vaf-Vbf/Vai-Cbi|
0.8=|Vaf-Vbf/5-7|
Vaf-Vbf=1.6
MaVa+mbVb=MaVaf+MbVbf
15*5*25*7=15Vaf+25Vbf
3Vaf+5Vbf=50
sovleving eq 1 and 2
Vbf =6.05 m/s
Vaf=7.65 m/s
The speed of a change in an object's location in any direction. The distance traveled divided by the time required to travel that distance is the definition of speed.Due to its lack of magnitude and merely having a direction, speed is a scalar number. The average speed of an object can be determined if you know the distance traveled and the time it took. Distance times speed is how speed is calculated.
Learn more about speed here:
brainly.com/question/28224010
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