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Georgia [21]
3 years ago
8

Please help me asap .

Physics
2 answers:
kupik [55]3 years ago
8 0

Answer:

We use the four properties of sound: pitch, dynamics (loudness or softness), timbre (tone color), and duration.

Daniel [21]3 years ago
5 0

Answer:

Dynamics, Duration, Pitch, Timbre! Hope this helped

Explanation:

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Pa answer po plsssss​
tankabanditka [31]

Refer to the attachment

4 0
3 years ago
Derive an expression for the energy needed to launch an object from the surface of Earth to a height h above the surface.Ignorin
Sergio [31]

Answer:

Explanation:

Potential energy on the surface of the earth

= - GMm/ R

Potential at height h

=  - GMm/ (R+h)

Potential difference

= GMm/ R -  GMm/ (R+h)

= GMm ( 1/R - 1/ R+h )

= GMmh / R (R +h)

This will be the energy needed  to launch an object from the surface of Earth to a height h above the surface.

Extra  energy is needed to get the same object into orbit at height h

= Kinetic energy of the orbiting object at height h

= 1/2 x potential energy at height h

= 1/2 x GMm / ( R + h)

8 0
4 years ago
algunas fabricas de balones de futbol ubicadas en la costa inflan los balones que van a ser vendidos en ciudades como pasto,tunj
solmaris [256]

Answer:

Debido al cambio de volumen del gas dentro de la bola cuando se somete a una disminución de la presión y un aumento de la temperatura de la atmósfera.

Explanation:

La ubicación de las fábricas que fabrican las bolas que se encuentra en la costa como se indica en la pregunta es a baja altitud y una región más fría donde la presión atmosférica es más alta

Por lo tanto, la presión en la costa = p₁

La temperatura en la costa = T₁

El volumen de la pelota en la costa = V₁

Las condiciones en una ciudad con mayor altitud y temperatura tienen mayor presión atmosférica y temperatura de la siguiente manera;

La presión en la ciudad = p₂ <p₁

La temperatura en la ciudad = T₂> T₁

El volumen de la pelota en la costa = V₂

Por la ley de gas combinada de tenemos;

\dfrac{p_1 \times V_1}{T_1} = \dfrac{p_2 \times V_2}{T_2}

Allí el volumen de la pelota en la ciudad estará dado por la relación;

V_2 = V_1 \times \dfrac{p_1 }{P_2} \times  \dfrac{ T_2}{T_1 }

Dado que p₁> p₂ y T₂> T₁, entonces p₁/p₂> 1 y T₂/T₁> 1 y tenemos;

V₂ = V₁ × p₁/p₂ × T₂/T₁ = V₁ × X, donde X = p₁/p₂ × T₂/T₁> 1

V₂ = V₁ × X (> 1)

Por lo tanto, V₂> V₁ y el volumen ocupado por el gas aumenta cuando la pelota llega a la ciudad y la pelota está más firme.

7 0
3 years ago
How long is a light year?
VashaNatasha [74]
A light year is = to 9.461 × 1015 metres
6 0
4 years ago
Read 2 more answers
A bumblebee is flying to the right when a breeze causes the bee to slow down with a constant leftward acceleration of magnitude
romanna [79]

Answer:

3.75 m/s

Explanation:

Given that a bumblebee is flying to the right when a breeze causes the bee to slow down with a constant leftward acceleration of magnitude 0.50 m/s^2. After 2.0 s the bee is moving to the right with a speed of 2.75 m/ s

What was the velocity of the bumblebee right before the breeze?

Since the breeze blows with the acceleration of 0.5 m/s^2 for 2 seconds, we can calculate the magnitude of the velocity at which it moves.

Acceleration = velocity/ time

Substitute the acceleration and time into the formula

0.5 = V/2

Cross multiply

V = 2 × 0.5

V = 1 m/s

The bumblebee is travelling right ward while the wind travels leftward.

The relative velocity = 2.75 m/s

Let the bumblebee speed = Vb

While the wind = VW

Vb - Vw = 2.75

Substitute the wind speed into the formula

Vb - 1 = 2.75

Vb = 2.75 + 1

Vb = 3.75 m/s

Therefore, the velocity of the bumblebee right before the breeze is 3.75 m/s

8 0
3 years ago
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