<u>Answer:</u> The entropy change of the liquid water is 63.4 J/K
<u>Explanation:</u>
To calculate the entropy change for same phase at different temperature, we use the equation:
where,
= Entropy change
= molar heat capacity of liquid water = 75.38 J/mol.K
n = number of moles of liquid water = 3 moles
= final temperature = ![95^oC=[95+273]K=368K](https://tex.z-dn.net/?f=95%5EoC%3D%5B95%2B273%5DK%3D368K)
= initial temperature = ![5^oC=[5+273]K=278K](https://tex.z-dn.net/?f=5%5EoC%3D%5B5%2B273%5DK%3D278K)
Putting values in above equation, we get:
Hence, the entropy change of the liquid water is 63.4 J/K
The chemical reaction between the reactants:
3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)
Explanation:
We have the following chemical reaction:
3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)
Complete ionic equation:
3 Ag⁺ (aq) + 3 NO₃⁻ (aq) + Fe³⁺ (aq) + 3 Cl⁻ (aq) → 3 AgCl (s) + Fe³⁺ (aq) + 3 NO₃⁻ (aq)
We remove the spectator ions and we get the net ionic equation:
Ag⁺ (aq) + Cl⁻ (aq) → AgCl (s)
where:
(aq) - aqueous
(s) - solid
Learn more about:
net ionic equation
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Answer:
3.3 moles of H₂O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4NH₃ + 5O₂ —> 6H₂O + 4NO
From the balanced equation above,
4 moles of NH₃ reacted to produce 6 moles of H₂O.
Finally, we shall determine the number of mole of H₂O produced by the reaction of 2.2 moles of NH₃. This can be obtained as follow :
From the balanced equation above,
4 moles of NH₃ reacted to produce 6 moles of H₂O.
Therefore, 2.2 moles of NH₃ will react to produce = (2.2 × 6)/4 = 3.3 moles of H₂O.
Thus, 3.3 moles of H₂O were obtained from the reaction.
Answer:
fluorine
Explanation:
The element fluorine has 9 protons and 9 electrons.
