Answer:
The answer to your question is SrCrO₄ + H₂O
Explanation:
Data
H₂CrO₄ + Sr(OH)₂ ⇒
We can notice that this is a Redox reaction or neutralization reaction because the reactants are an acid (H₂CrO₄) and a base (Sr(OH)₂). These reactions are also called double displacement reactions.
In these kind of reactions the products are always a binary or ternary salt and water.
Then, for this reaction,
H₂CrO₄ + Sr(OH)₂ ⇒ SrCrO₄ + H₂O
Answer:
The correct answer is - yes, 4.57 g of solute per 100 ml of solution
Explanation:
The correct answer is yes we can calculate the solubility of X in the water at 22.0°C. The salt will remain after the evaporate from the dissolved and cooled down at 26°C.
Then, the amount of solute dissolved in the 700 ml solution at 26°C is the weighed precipitate: 0.032 kg = 32 g.
Then solublity will be :
32. g solute / 700 ml solution = y / 100 ml solution
⇒ y = 32. g solute × 100 ml solution / 700 ml solution = 4.57 g.
Thus, the answer is 4.57 g of solute per 100 ml of solution.
Answer: The number of grams of 
in 1620 mL is 1.44 g
Explanation:
According to ideal gas equation:
P = pressure of gas = 1 atm (at STP)
V = Volume of gas = 1620 ml = 1.62 L (1L=1000ml)
n = number of moles = ?
R = gas constant =
T =temperature =
Mass of hydrogen =
The number of grams of in 1620 mL is 1.44 g
B. reproduction doesn’t require mate
Answer: d. both (b) and (c)
Explanation:
Atoms are too small to be seen on microscopes, so we model them based on theories.
