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Igoryamba
2 years ago
14

5. The atomic number of an element is equal to:

Chemistry
2 answers:
Trava [24]2 years ago
4 0
The number of protons in the atom, A.
Degger [83]2 years ago
3 0
A. the number of protons in the atoms
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What is an air pressure system?
Anna35 [415]

Answer:

"The number of air molecules above a surface determines air pressure. As the number of molecules increases, they exert more pressure on a surface, and the total atmospheric pressure increases. By contrast, if the number of molecules decreases, so too does the air pressure."

7 0
2 years ago
What mass of carbon dioxide is produced from the complete combustion of 4.50×10−3 g of methane?
ivanzaharov [21]

CH₄ + 2O₂ → CO₂ + 2H₂O

From the equation, we know that methane and carbon dioxide have the same number of moles.

no. of moles = \frac{mass}{molar mass}

no. of moles of CO₂ produced = no. of moles of methane

= 4.5 × 10⁻³ ÷ (12 + 1×4)

= 2.8125 × 10⁻⁴

∴ mass of CO₂ = 2.8125 × 10⁻⁴ × (12 + 16×2)

= 12.375 × 10⁻³ g

4 0
3 years ago
The reaction of equal molar amounts of benzene, C6H6, and chlorine, Cl2, carried out under special conditions, yields a gas and
WINSTONCH [101]

Answer : The molecular formula of a compound is, C_6H_5Cl_1

Solution : Given,

Mass of C = 64.03 g

Mass of H = 4.48 g

Mass of Cl = 31.49 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of Cl = 35.5 g/mole

Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{64.03g}{12g/mole}=5.34moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{4.48g}{1g/mole}=4.48moles

Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{31.49g}{35.5g/mole}=0.887moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{5.34}{0.887}=6.02\approx 6

For H = \frac{4.48}{0.887}=5.05\approx 5

For Cl = \frac{0.887}{0.887}=1

The ratio of C : H : Cl = 6 : 5 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = C_6H_5Cl_1

The empirical formula weight = 6(12) + 5(1) + 1(35.5) = 112.5 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{112.5}{112.5}=1

Molecular formula = (C_6H_5Cl_1)_n=(C_6H_5Cl_1)_1=C_6H_5Cl_1

Therefore, the molecular of the compound is, C_6H_5Cl_1

5 0
3 years ago
A picture of a patient’s lung showed it to be shriveled and darker than usual.
Strike441 [17]

Answer:

Smoking

Explanation:

It has been proven time and time again to ruin lungs, effectively shortenning ones lifespan.

3 0
3 years ago
Read 2 more answers
What do scientists use to increase the surface area of a solute?
mojhsa [17]
<span>use a mortar & pestle to grind the solute into smaller particles, thus increasing the surface area.</span>
5 0
3 years ago
Read 2 more answers
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