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Kamila [148]
3 years ago
12

Muscle contraction is triggeredA) in response to an increase in the cytoplasmic Ca2+concentration.B) in response to a decrease i

n the cytoplasmic Ca2+concentration.C) in response to an increase in the cytoplasmic cAMP concentration.D) in response to a decrease in the cytoplasmic cAMP concentration.E) in response to an increase in the cytoplasmic titin concentration.
Chemistry
1 answer:
natima [27]3 years ago
4 0

Answer:

A) in response to an increase in the cytoplasmic Ca2+concentration.

Explanation:

Muscle contraction occurs in response to an increase in the cytoplasmic Ca2 + concentration.

This process occurs with the shortening of the sarcomeres resulting in a result, the actin filaments react with myosin, generating actomyosin. During this reaction, it is necessary to increase the cytoplasmic concentration of Ca + and ATP. In this, myosin will break down ATP, releasing energy so that the muscle can contract.

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What number do you get when you multiply 6 and 7 together?
dem82 [27]

You get 42 when you multiply 6 & 7.

4 0
4 years ago
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Consider a sample of calcium carbonate in the form of a cube measuring 2.805 in. on each edge.
Naya [18.7K]

Answer:

The answer to your question is: 8.82 x 10 ²⁴ atoms of oxygen          

Explanation:

Data

Cube measuring : 2.805in on each edge

density = 2.7 g/cm3

# of oxygen atoms in the cube = ?

Process

Volume of the cube = (2.805)³ = 22.07 in³

Convert in³ to cm³                  1 in³   -------------------  16.39 cm³

                                       22.07 in³    --------------------    x

                        x = (22.07 x 16.39) / 1 = 361.72 cm³

Density = mass / volume

Mass = density x volume

Mass = (2.7)(361.72) = 976.66 g

Atomic mass CaCO3 = 40 + 12 + (16 x 3) = 100 g

                                100 g of CaCO3 --------------------  48 g of O2

                                976.66 g of CaCO3 ---------------    x

                           x = (976.66 x 48) / 100 = 468.8 g of O2

                              32 g of O2 ----------------------  1 mol

                           468.8 g of O2 --------------------   x

                       x = (468.8 x 1) / 32 = 14.65 mol

                           1 mol -----------------------   6.023 x 10 ²³ atoms

                        14.65 mol -------------------    x

                    x = (14.65 x 6.023 x 10 ²³) / 1 = 8.82 x 10 ²⁴ atoms of oxygen          

3 0
3 years ago
What is the molecular weight of one mole of H₂CO3?
adelina 88 [10]

Answer:

The molecular weight 62,03 g/mol

7 0
2 years ago
Please help ASAP I’ll mark you as brainlister
EastWind [94]

Answer:

2

Explanation:

The balanced chemical equation for this reaction is:

2Na + K2S → 2K + Na2S

Meaning the coefficient for potassium (K) is 2.

4 0
3 years ago
Read 2 more answers
A 0.65 M solution of an unknown amine base is found to be 2.2% ionized at equilibrium. Calculate the value for Kb for this amine
mihalych1998 [28]

The value of Kb of the unknown amine is 3.22 x 10^-4.

Weak electrolytes:

The compound which do not dissociate completely when added to the aqueous solution are called weak electrolytes. The electrolyte and its ions exists in equilibrium. In case of weak base, the equilibrium constant is expressed as Kb.

Calculations:

Step 1:

The percentage of amine ionized at equilibrium is 2.2%.

NH3   +     H2O ------>    NH4+   +    OH-

The concentration of conjugate acid at equilibrium is calculated as:

2.2 = (x/0.65) x 100

x = 0.0143 M

Step 2:

The equilibrium constant (Kb) is calculated as:

Kb = x^2/0.65 - x

= (0.0143)^2/(0.65 - x)

= 3.22 x 10^-4

Learn more about weak electrolytes here:

brainly.com/question/19340043

#SPJ4

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2 years ago
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