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3 years ago

Identify the element whose highest energy electron would have the following four quantum numbers?

Chemistry

1 answer:

ad-work [718]3 years ago

4 0

C. 6, 1, 0, -1/2

Explanation:

The four quantum numbers are:

Principal quantum number (n): this represents the energy level in which an orbital is located.
Azimuthal quantum number gives the shape of the orbitals in subshells accommodating the electrons.
Magnetic quantum number gives the number of spatial orientations or degeneracy of the orbitals in the subshells.
Spin quantum number describes the spinning of an electron in either clockwise or anticlockwise directions.

To know the electron with the highest energy, we use the principal quantum number values.

n values takes whole numbers i.e n = 1,2,3,4,5,6,7.............

The higher the value, the higher the energy level.

From the given quantum numbers, C has the highest energy levels.

Learn more;

Quantum numbers brainly.com/question/9288609

#learnwithBrainly

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Read 2 more answers

When aqueous solutions of K3PO4 and Ba(NO3)2 are combined, Ba3(PO4)2 precipitates. Calculate the mass, in grams, of the Ba3(PO4)

Firdavs [7]

Answer:

Mass of Ba₃(PO₄)₂ = 0.0361 g

Explanation:

Given data:

Volume of Ba(NO₃)₂ = 1.2 mL (1.2 × 10⁻³ L )

Molarity of Ba(NO₃)₂ = 0.152 M

Volume of K₃PO₄ = 4.2 mL (4.2 × 10⁻³ L)

Molarity of K₃PO₄ = 0.604 M

Mass of Ba₃(PO₄)₂ produced = ?

Solution:

Chemical equation:

3Ba(NO₃)₂ + 2K₃PO₄ → Ba₃(PO₄)₂ + 6KNO₃

Number of moles of Ba(NO₃)₂ = Molarity × Volume in litter

Number of moles of Ba(NO₃)₂ = 0.152 M × 1.2 × 10⁻³ L

Number of moles of Ba(NO₃)₂ = 0.182 × 10⁻³ mol

Number of moles of K₃PO₄ = Molarity × Volume in litter

Number of moles of K₃PO₄ = 0.604 M × 4.2 × 10⁻³ L

Number of moles of K₃PO₄ = 2.537 × 10⁻³ mol

Now we will compare the moles of Ba₃(PO₄)₂ with K₃PO₄ and Ba(NO₃)₂ .

Ba(NO₃)₂ : Ba₃(PO₄)₂

3 : 1

0.182 × 10⁻³ : 1/3 ×0.182 × 10⁻³ = 0.060 × 10⁻³ mol

K₃PO₄ : Ba₃(PO₄)₂

2 : 1

2.537 × 10⁻³ : 1/2 × 2.537 × 10⁻³= 1.269 × 10⁻³ mol

The number of moles of Ba₃(PO₄)₂ produced by Ba(NO₃)₂ are less it will limiting reactant.

Mass of Ba₃(PO₄)₂ = moles × molar mass

Mass of Ba₃(PO₄)₂ = 0.060 × 10⁻³ mol × 601.93 g/mol

Mass of Ba₃(PO₄)₂ = 36.12 × 10⁻³ g

Mass of Ba₃(PO₄)₂ = 0.0361 g

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Using the VSEPR theory , what would the representation mean A central atom with 2 connected atoms atom with I lone pair of Jone

VLD [36.1K]

Answer:

The molecule has a bent geometry

Explanation:

Let us look again at the principles of VSEPR theory. The shape of a molecule depends on the number of electron pairs that surround the valence shell of the central atom in the molecule.

Lone pairs distort the molecular geometry away from what is expected on the basis of VSEPR theory.

The molecule described in the question has the form AEX2. Two substituents and one lone pair form three electron domains around the central atom. The expected geometry is trigonal planar but the observed molecular geometry is bent because of the lone pairs present.

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