All categories

3 years ago

Identify the element whose highest energy electron would have the following four quantum numbers?

Chemistry

1 answer:

ad-work [718]3 years ago

4 0

C. 6, 1, 0, -1/2

Explanation:

The four quantum numbers are:

Principal quantum number (n): this represents the energy level in which an orbital is located.
Azimuthal quantum number gives the shape of the orbitals in subshells accommodating the electrons.
Magnetic quantum number gives the number of spatial orientations or degeneracy of the orbitals in the subshells.
Spin quantum number describes the spinning of an electron in either clockwise or anticlockwise directions.

To know the electron with the highest energy, we use the principal quantum number values.

n values takes whole numbers i.e n = 1,2,3,4,5,6,7.............

The higher the value, the higher the energy level.

From the given quantum numbers, C has the highest energy levels.

Learn more;

Quantum numbers brainly.com/question/9288609

#learnwithBrainly

You might be interested in

How many neutrons are in an atom with atomic number of 53 and mass number of 127?

asambeis [7]

Atomic number = 127 – 53=74 neutrons

8 0

2 years ago

For the same mixture, under the same conditions described in problem 7, calculate keq for 2nh3 (g) n2 (g) + 3h2(g). how is the k

nekit [7.7K]

Answer: The relation between the forward and reverse reaction is $K_f=\frac{1}{K_r}$

Explanation:

For the given chemical equation:

$2NH_3(g)\rightleftharpoons N_2 (g)+3H_2(g)$

The expression of equilibrium constant for above equation follows:

$K_f=\frac{[N_2][H_2]^3}{[NH_3]^2}$ .......(1)

The reverse equation follows:

$N_2 (g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

The expression of equilibrium constant for above equation follows:

$K_r=\frac{[NH_3]^2}{[N_2][H_2]^3}$ .......(2)

Relation expression 1 and expression 2, we get:

$K_f=\frac{1}{K_r}$

Hence, the relation between the forward and reverse reaction is $K_f=\frac{1}{K_r}$

7 0

2 years ago

35mL of acid with an unknown concentration is titrated to completion using 63mL of 3.0 MNaOH.

siniylev [52]

Answer:

5.4 M.

Explanation:

At complete neutralization: It is known that the no. of millimoles of acid equal that of the base.

(MV)acid = (MV)NaOH

M of acid = ??? M, V of acid = 35.0 mL.

M of NaOH = 3.0 M, V of NaOH = 63.0 mL.

∴ M of acid = (MV)NaOH / (V)acid = (3.0 M)(63.0 mL)/(35.0 mL) = 5.4 M.

4 0

2 years ago

Why is there not a corresponding drop in ionization energies between Bi and Po in the sixth period as N and O?

Stels [109]

Answer:

See explanation

Explanation:

According to the Journal of Chemical Education, Volume 80, No.8 (2003); "The first ionization energy of bismuth appears to be anomalous......It has been claimed that spin– orbit coupling by the Russell–Saunders scheme would lower the ground state of Bi+ ..."

However, the involvement of d and f orbitals in Bi and Po implies that the outermost orbitals are poorly screened hence the drop between nitrogen and oxygen is not observed between Bi and Po.

The same argument could be extended to explain the reason why there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B.

3 0

2 years ago

Sholpan [36]

Answer: Your mass would be the same, but you would weigh less because the gravity on the moon is less than it is on Earth.

Explanation:

7 0

2 years ago