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3 years ago

Identify the element whose highest energy electron would have the following four quantum numbers?

Chemistry

1 answer:

ad-work [718]3 years ago

4 0

C. 6, 1, 0, -1/2

Explanation:

The four quantum numbers are:

Principal quantum number (n): this represents the energy level in which an orbital is located.
Azimuthal quantum number gives the shape of the orbitals in subshells accommodating the electrons.
Magnetic quantum number gives the number of spatial orientations or degeneracy of the orbitals in the subshells.
Spin quantum number describes the spinning of an electron in either clockwise or anticlockwise directions.

To know the electron with the highest energy, we use the principal quantum number values.

n values takes whole numbers i.e n = 1,2,3,4,5,6,7.............

The higher the value, the higher the energy level.

From the given quantum numbers, C has the highest energy levels.

Learn more;

Quantum numbers brainly.com/question/9288609

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Given the data calculated in Parts A, B, C, and D, determine the initial rate for a reaction that starts with 0.85 M of reagent

elixir [45]

Answer : The initial rate for a reaction will be $3.8\times 10^{-4}Ms^{-1}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The chemical equation will be:

$A+B+C\rightarrow P$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b[C]^c$

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

$6.1\times 10^{-5}=k(0.2)^a(0.2)^b(0.2)^c$ ....(1)

Expression for rate law for second observation:

$1.8\times 10^{-4}=k(0.2)^a(0.2)^b(0.6)^c$ ....(2)

Expression for rate law for third observation:

$2.4\times 10^{-4}=k(0.4)^a(0.2)^b(0.2)^c$ ....(3)

Expression for rate law for fourth observation:

$2.4\times 10^{-4}=k(0.4)^a(0.4)^b(0.2)^c$ ....(4)

Dividing 1 from 2, we get:

$\frac{1.8\times 10^{-4}}{6.1\times 10^{-5}}=\frac{k(0.2)^a(0.2)^b(0.6)^c}{k(0.2)^a(0.2)^b(0.2)^c}\\\\3=3^c\\c=1$

Dividing 1 from 3, we get:

$\frac{2.4\times 10^{-4}}{6.1\times 10^{-5}}=\frac{k(0.4)^a(0.2)^b(0.2)^c}{k(0.2)^a(0.2)^b(0.2)^c}\\\\4=2^a\\a=2$

Dividing 3 from 4, we get:

$\frac{2.4\times 10^{-4}}{2.4\times 10^{-4}}=\frac{k(0.4)^a(0.4)^b(0.2)^c}{k(0.4)^a(0.2)^b(0.2)^c}\\\\1=2^b\\b=0$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^0[C]^1$

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

$6.1\times 10^{-5}=k(0.2)^2(0.2)^0(0.2)^1$

$k=7.6\times 10^{-3}M^{-2}s^{-1}$

Now we have to calculate the initial rate for a reaction that starts with 0.85 M of reagent A and 0.70 M of reagents B and C.

$\text{Rate}=k[A]^2[B]^0[C]^1$

$\text{Rate}=(7.6\times 10^{-3})\times (0.85)^2(0.70)^0(0.70)^1$

$\text{Rate}=3.8\times 10^{-3}Ms^{-1}$

Therefore, the initial rate for a reaction will be $3.8\times 10^{-3}Ms^{-1}$

6 0

3 years ago

The molecule with the largest dipole moment (a) co2 (b) h2o (c) ch4 (d) c2h4 (e) ph3

storchak [24]

The molecule with the largest dipole moment will be $CH_{4}$ .

A dipole moment would be a unit used to describe how far apart two electrical charges are from one another. Dipole moments represent a type of vector. The direction could be from negative charge to positive charge, while the magnitude has been equal to the charge times the distance between most of the charges.

The polar bonds, of $CO_{2}$ as well as $H_{2} O$ have chemical configurations where the polarity cancels, leaving no net dipole. Regardless of the molecule's shape, $CH_{4}$ lacks a net dipole due to its non-polar links.

The molecule with the largest dipole moment will be $CH_{4}$ .

Hence the correct answer will be option (c).

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2 years ago

How many orbitals exist for s shape

xenn [34]

The s sublevel has only one orbital

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A bottle sitting on a table has no forces at all acting upon it.

solong [7]

Answer:

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Explanation:

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Paha777 [63]

Explanation:

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Example:

The carbon atom in coal becomes carbon dioxide when it is burned. The carbon atom changes from a solid structure to a gas but its mass does not change.

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3 years ago