Answer:
156.24N
Explanation:
From the data above;
Mass = 23g = 0.023kg
V = 88m/s
Kinetic energy = ½mv²
K.e = ½* 0.023 * 88²
K.E = 89.056J
The force required to accelerate the arrow to that speed and energy in 0.57m
Using equation of motion;
V² = U² + 2as
But U =0
V² = 2as
a = v²/2s
a = 88² / (2*0.57)
a = 6792.98m/s²
The force (F) that accelerates the arrow with that velocity = ?
F = M*a
F = 0.023 * 6792.98
F = 156.24N
Answer:
The answer is below
Explanation:
Given that the mass of the sculpture (m) = 6.2 kg,
Answer:
Explained
Explanation:
A student who runs every day is becoming bored with her physical fitness routine and considers quitting. Now in order maintain her fitness routine she needs to break the monotony by changing her exercise regime. She do other activities like play sports two days a week, she do aerobics, she even try some cardio vascular exercises which as good as running. She also try changing her route of running as the new view might inspire her.
Answer:
p = 49.95 cm
This is the distance from the student to the stepped, in order to be able to reach this distance they must sit in the first row
Explanation:
In medicine it is very common to express the potential visual corrections that is
P = 1 / f
where P is the power and f the focal length in meters
In this exercises give the power, let's find the focal length
f = 1 / p
f = 1/52
f = 0.01923 m = 1.923 cm
For geometrical optics calculations the most used equation is the constructor equation
1 / f = 1 / p + 1 / q
Where p and q are the distance to the object and the image, respectively
To be able to see an object clearly, its image must be on the retina,
q = 2.00 cm
find the distance to the object
1 / p = 1 / f - 1 / q
1 / p = 1 / 1,923 - 1/2.00
1 / p = 0.02002
p = 49.95 cm
This is the distance from the student to the stepped, in order to be able to reach this distance they must sit in the first row