Well you have to think of it like electricity go through your answer closes to that and figure it out
The distance that would be accumulated during the journey is 2.5 meters
The parameters given in the question are written below;
average speed= 5 km/hr
time = 30 minutes
convert 30 minutes to hours
= 30/60
= 0.5 hours
Distance-= speed × time
= 5 × 0.5
= 2.5 meters
Hence the distance of the entire journey is 2.5 meters
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Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".
Solution:
The fundamental frequency in a standing wave is given by

where L is the length of the string, T the tension and m its mass. If we plug the data of the problem into the equation, we find

The wavelength of the standing wave is instead twice the length of the string:

So the speed of the wave is

And the time the pulse takes to reach the shop is the distance covered divided by the speed:
The frequency, f, of a wave is the number of waves passing a point in a certain time. We normally use a time of one second, so this gives frequency the unit hertz (Hz), since one hertz is equal to one wave per second.
Answer: C. 1.64 x 10-3 m/s2