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NeTakaya
2 years ago
7

On question 2 How did you get 20.8% from 48.08/10 •100?

Chemistry
1 answer:
Ilia_Sergeevich [38]2 years ago
3 0

thank you sincerely for the points. you are very generous and kind to hand over these wonderful points. you went out of your way to clear the dust, shake the ground, and give me epic points. you are such a great person almost better than jorge washington himself.

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A solution of AgNO3 contains 29.66 g of solute in 100.0 mL of solution. What is the molarity of the solution
Julli [10]

Answer:

1.7 M

Explanation:

Given data:

Mass of AgNO₃ = 29.66 g

Volume of solution = 100 mL (100/1000 = 0.1 L)

Molarity of solution = ?

Solution;

Number of moles of AgNO₃:

Number of moles = mass/ molar mass

Number of moles = 29.66 g/ 169.87 g/mol

Number of moles = 0.17 mol

Molarity of solution:

Molarity =  moles of solute / volume of solution in L

Molarity = 0.17 mol / 0.1 L

Molarity = 1.7 M

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