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Deffense [45]
2 years ago
14

Short, difficult activities that push your body are called

Physics
2 answers:
Reika [66]2 years ago
4 0

Answer: A

Explanation: Any short-duration exercise that is powered primarily by metabolic pathways that do not use oxygen. Examples

of anaerobic exercise include sprinting and weight lifting.

goldenfox [79]2 years ago
3 0

Answer:

B. is your answer

Explanation:

Have a good day

Sincerly, lipor

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What happens to a liquid when it loses energy
NeTakaya
It can solidify, it depends on the tempeture.
8 0
3 years ago
Blue to gray in color and reaching up to 10 feet (3.05 meters) in length and 220 pounds (99.8 kilograms) in weight, the sailfish
vagabundo [1.1K]

Answer:

the distance traveled by the fish is 3648 m

Explanation:

In general, animals have a small period of acceleration, which we will despise after which they travel at a constant speed so we can use the kinematic equations in uniform motion

   

We reduce the units to System SI

      t = 2 min (60s / 1 min) = 120 s

Calculate

       V = x / t

       x= V t

       x = 30.4 120

       x = 3648 m

 

This is the distance traveled by the fish

6 0
3 years ago
At the time of the founding of the country, most Americans worked as
STatiana [176]

Answer:

Farmers

Explanation:

At the time of founding our country most soldiers in the revolutionary war were farmers who were inexperienced.

4 0
2 years ago
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3 years ago
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A 2.31 kg rope is stretched between supports 10.4 m apart. If one end of the rope is tweaked, how long will it take for the resu
zlopas [31]

Answer:

t = 0.657 s

Explanation:

First, let's use the appropiate equations to solve this:

V = √T/u

This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.

Where:

V: Speed of the disturbance

T: Tension of the rope

u: linear density of the rope.

The density of the rope can be calculated using the following expression:

u = M/L

Where:

M: mass of the rope

L: Length of the rope.

We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:

u = 2.31 / 10.4 = 0.222 kg/m

Now, replacing in the first equation:

V = √55.7/0.222 = √250.9

V = 15.84 m/s

Finally the time can be calculated with the following expression:

V = L/t ----> t = L/V

Replacing:

t = 10.4 / 15.84

t = 0.657 s

4 0
3 years ago
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