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earnstyle [38]
4 years ago
5

A sinusoidal transverse wave travels along a long, stretched string. The amplitude of this wave is 0.08190.0819 m, its frequency

is 2.292.29 Hz, and its wavelength is 1.871.87 m. (a) What is the shortest transverse distance between a maximum and a minimum of the wave
Physics
1 answer:
Anvisha [2.4K]4 years ago
5 0

Answer:

The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.

Explanation:

Given that,

Amplitude = 0.08190 m

Frequency = 2.29 Hz

Wavelength = 1.87 m

(a). We need to calculate the shortest transverse distance between a maximum and a minimum of the wave

Using formula of distance

d=2A

Where, d = distance

A = amplitude

Put the value into the formula

d=2\times0.08190

d=0.1638\ m

Hence, The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.

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About 2% of our solar nebula consisted of elements besides hydrogen and helium. However, the very first generation of star syste
Mariulka [41]

Answer:

Answer

Explanation:

The very first generation of star systems in the universe probably consisted only of hydrogen and helium. This means that,

There were no comets or asteroids in these first-generation star systems. As the comets and asteroids were the only soruce of elements other than Hydrogen and Heliums ( As starts mainly consists of helium and hydrogen).

3 0
3 years ago
A tank is shaped like an upside-down square pyramid, with a base with sides that are 4 meters in length and a height of 12 meter
xeze [42]
Hello!

I included a link that might help you in terms of how the problem is broken down.

https://www.slader.com/discussion/question/a-tank-is-shaped-like-an-upside-down-square-pyramid-with-base-of-4m-by-4m-and-a-height-of-12m-how-fa/

However, the answer is:

The height increases at 3/2 m/sec
4 0
4 years ago
What is the wavelength of red light in vacuum that has a frequency of 4.00 × 1014 hz?
Pachacha [2.7K]

Answer: 7.5(10)^{-7} m

Explanation:

The frequency \nu of an electromagnetic wave is given by the following equation:  

\nu=\frac{c}{\lambda}  

Where:  

c=3(10)^{8} m/s is the speed of light  in vacuum

\nu=4(10)^{14} Hz is the frequency of red light

\lambda   is the wavelength of red light

Isolating \lambda:

\lambda=\frac{c}{\nu}  

\lambda=\frac{3(10)^{8} m/s}{4(10)^{14} Hz}  

Finally:

\lambda=7.5(10)^{-7} m  

6 0
4 years ago
Which statement would be a valid argument in favor of using nuclear power? There are few negative impacts from mining the fuel.
fgiga [73]
Okay so, lets use the process of elimination here. 

<span>A)There are few negative impacts from mining the fuel.
B)Reactors are safe from natural disasters.
C)There are little to no waste products from fission.
D)Nuclear power does not contribute greenhouse gases.

First off, we know B cannot be correct, seeing as how reactors are fragile and are damaged easily by Japan's earthquakes. So we can eliminate B from the choices. We then can eliminate C, since fission creates high levels of nuclear waste, so that leaves us with just A, and D. We can then eliminate A since uranium is radioactive, there is always a chance for negative effects.

So, the correct answer is D</span>
6 0
3 years ago
Read 2 more answers
a sound wave travels at 330 m/sec and has a wavelenght of 2meters. calcuate the frequency and period
Sergio039 [100]

The frequency of any wave is  (speed) / (wavelength).

 Frequency = (330 m/s) / (2m)  =  165 per second = <em>165 Hz</em>.

Period = 1 / frequency  =  1 / (165 per second) = <em>0.0061 second </em>


7 0
3 years ago
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