Answer:
We have to take the two axes of coordinates, the X axis & the Y axis, and perform the equation of sum of forces on each of the X & y axes. In order to find the value of the respective forces. We can also perform summations of moments around a given point to find unknowns in deduced equations.
Explanation:
A free body diagram gives us a summary of the forces acting on a body. These forces can be equal to zero. Or equal to the product of its mass by acceleration.
Although in some cases special attention should be paid to the movement of the body by such forces, for example if the movement is at constant speed, the acceleration will be equal to zero. Therefore the sum of forces will be equal to zero when the speed is constant.
Finally we have to take the two axes of coordinates, the X axis & the Y axis, and perform the equation of sum of forces on each of the X & y axes. In order to find the value of the respective forces.
We can also perform summations of moments around a given point to find unknowns in deduced equations.
In the attached image we can see a beam which is subjected to loads, and performing a summation of moments around the pivoting point equal to zero (the beam is in balance) we can find the value of force F.
The work and heat transfer isothermal internally reversible process.
An isothermal procedure is a thermodynamic procedure in which the temperature of a gadget stays consistent. The transfer of heat into or out of the gadget occurs so slowly that thermal equilibrium is maintained. The melting of ice at 0 diploma is an example of isothermal technique. The reaction in a warmth pump is an example of isothermal manner. In Isothermal manner temperature is constant for the duration of the procedure and follows Boyles regulation.
Given,
Gas at initially P1= 2.8 bar
P2 = 14 bar
isothermal reversible process,
Compressed pressure at 60°C
(a) R = 134a
For Refrigerant 134a R134a
At P1 = 14 bar T1 = 600C
S1 = 0.9389 KJ/Kg K
V1 = 264.64 KJ/kg
At
P2 = 2.8 bar T2 = 600C
S2 = 1.1142 KJ/Kg K
V2 = 278.56 KJ/kg
T = 60 + 273 = 333K
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
= 333 ( 1.1142 - 0.9389 )
= 58.3749 KJ/Kg
Heat transfer Q = 58.3749 KJ/Kg
(b) air as an ideal gas.
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
=T-R In P2 P1
= 333 * -0.287 In 2.8 14
= 153.81 KJ/Kg
Heat transfer Q = 153.81 KJ/Kg
W = Q - ΔV
= 28.3749 - (278.56-264.64)
= 14.4549 KJ/Kg
Work W = 14.4549 KJ/Kg
Learn more about isothermal process here:-brainly.com/question/17097259
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(a) The wavelength of the wave for the fundamental mode is 2.4 m.
(b) The fundamental frequency of the wave is 2,708.33 Hz.
<h3>Wavelength of the wave for fundamental mode</h3>
The wavelength of the wave for the fundamental mode is calculated as follows;
Node to Node, N → N = λ/2
L = λ/2
λ = 2L
λ = 2 x 1.2
λ = 2.4 m
<h3>Fundamental frequency of the wave</h3>
The fundamental frequency of the wave is calculated as follows;
f = v/λ
f₀ = v/2L
f₀ = (6500)/(2 x 1.2)
f₀ = 2,708.33 Hz
The diagram of the wave for the fundamental mode is in the image uploaded.
Learn more about wavelength here: brainly.com/question/10728818
average velocity is vector displacement / time
time is "almost exactly one hour"
disp = -10m
v= -10/1x60x60 = -1/360m/s