Answer: 405.3 minutes
Explanation: In order to explain this problem we have to use the following:
Fisrtly we calculate the volume of the wire, this is given by:
Vwire=π*r^2*L where r and L are the radius and L the length of teh wire, respectively.
Vwire=π*1.25*10^-3*0.26=1.27*10^-6 m^3
then the number of the total electrons in tthe wire volume is given by;
n° electrons in the wire=ρ*Vwire=8.4*10^28*1.27*10^-6 m^3=1.07 *10^23
Finally, considering the current in the wire equal to 4.4*10^18 electrons/s
the time consuming to extract all the electrons from the wire is given by:
t= total electrons in the wire/ current=1.067*10^23/4.4*10^18=24,318 s
equivalent to 405.3 minutes
Answer:
Explanation:
1) acceleration is the change in velocity of a body with respect to time.
acceleration = velocity/time
Given
velocity = 139m/s
time = 20secs
acceleration = 139/20
acceleration = 6.95m/s²
Hence its average acceleration during the first 20 seconds of the launch is 6.95m/s²
2) Speed is the rate of change of distance with respect to time.
average speed = distance/time
Time = distance/speed
Time = 100/7823
Time = 0.013s
3) Using the equation of motion v² = u²+2as
v² = 0²+2(15)(60)
v² = 30*60
v² =1800
v = √1800
v = 42.43m/s
First harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
<h3>
First harmonic of a closed pipe</h3>
The first harmonic of a closed pipe is the fundamental frequency of the closed of the closed pipe.
L = λ/4
where;
- L is the length of the pipe
- λ is the wavelength of sound
λ = 4L
But, v = F₀λ
v = F₀(4L)
F₀ = v/4L
where;
- F₀ is the first harmonic
- v is speed of sound
Thus, first harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
Learn more about fundamental frequency here: brainly.com/question/1967686
#SPJ11
<h3 />
'Displacement' is the distance and direction between the starting point and
ending point, regardless of the path followed to get there.
A particle that's executing simple harmonic motion is always in the same place
where it was one time period ago, and where it will be later after another time
period has passed.
So its displacement during exactly one time period is exactly zero.
Answer:
The electric potential difference is 32500 volt.
Explanation:
Given that,
Charge
Energy = 6.5 J
We need to calculate the electric potential difference
Potential difference :
Potential difference is equal to the energy divide by charge.
Using formula of potential difference
Hence, The electric potential difference is 32500 volt.
