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Eddi Din [679]
2 years ago
7

PLEASE HELP!!!!!!!!!!!!!!!

Mathematics
1 answer:
GarryVolchara [31]2 years ago
7 0

Answer:

C) 3/8

Step-by-step explanation:

Find 1/8 + 1/4

1/8 + 1/4

= 1/8 + 2/8

= 3/8

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uysha [10]

Answer:

1) 0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588    

0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219    

b) ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653

And we want 2/3 of the margin of error so then would be: 2/3 ME = 0.00001111

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (2)

Replacing we got:

n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=0.0826052 represent the sample mean

\mu population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size  

Part 1

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom, given by:

df=n-1=5-1=4

The Confidence level is 0.95 or 95%, and the significance would be \alpha=0.05 and \alpha/2 =0.025, the critical value would be using the t distribution with 4 degrees of freedom: t_{\alpha/2}=2.776

Now we have everything in order to replace into formula (1):

0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588    

0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219    

Part 2

The original margin of error is given by:

ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653

And we want 2/3 of the margin of error so then would be: 2/3 ME = 0.00001111

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (2)

Replacing we got:

n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12

So the answer for this case would be n=12 rounded up to the nearest integer

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3 years ago
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Setler79 [48]
You just do 40 times 0.825 and you will get your answer. 
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Worth 25 points, giving brainiest to a quick and good answer.
vredina [299]

Answer:


Step-by-step explanation:

Note that the quadratic formula has that "plus or minus" due to our taking the square root of some quantity.  No square root is involved in the two formulas you've posed.

I have two suggestions here:

1) Write " (x plus or minus y)^2 = x^ plus or minus 2 times xy + y^2 "  Note that a + on the left side corresponds to a + on the right side, and same with - .

2) Memorize these two formulas, which in most algebra textbooks you'll find in the section "special products and factoring."


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3 years ago
the ratio of students to teachers on the field trip is 1 to 13.If there are 22 teachers going on the trip,how many students are
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Answer:

286

Step-by-step explanation:

multiply 13 by 22.

boom

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Write a number that is between each pair of numbers 17 _ 23 39_ 44
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Well the gap in first number is 6 and in other is 5 is it a correct sequence?
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