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My name is Ann [436]
2 years ago
8

What do i do on this rubixs cube

Physics
2 answers:
fredd [130]2 years ago
5 0

Answer:

you just spin it and spin it and spin it                                                                                                                   and spin it                      

and spin it

and spin it

and spin it

and spin it

until you get mad then throw it at the wall

Explanation:

ya then you look up a vid that is called rubix cube meme and there should be a pink animal its funny you should watch it!!!!!!!!!

julsineya [31]2 years ago
4 0

Answer:

You solve it

Explanation:

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Answer: I think the answer is D.

Positively charged particles.

8 0
3 years ago
I WILL MARK BRAINLIEST IF CORRECT!!!
julsineya [31]

0.05*0.2=0.05*0.15+0.015*m2',

m2'=1/6 m/s,

m2'=0.17 m/s

N I C E - D A Y!

6 0
3 years ago
How long will it take you to pass a truck at 60 mph with oncoming traffic?
DedPeter [7]
<span>This is impossible to calculate without knowing the speed of each vehicle. </span>
6 0
3 years ago
Read 2 more answers
A large bar magnet (mass of 0.4 kg) exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away. Calculate the
Gwar [14]

Answer:

5 N

Explanation:

Given that,

A large bar magnet of mass 0.4 kg exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away.

We need to find the force exerted by the small bar magnet on the large one.

We know that, every action has an equal and opposite reaction. Both action and reaction occur in pairs. The force acting on one object to another is same and in opposite direction on the other object.

Hence, the force exerted by the small bar magnet on the large one is also 5 N.

4 0
3 years ago
A rock of mass m is thrown horizontally off a building from a height h. the speed of the rock as it leaves the thrower's hand at
Stells [14]
The correct answer is <span>3) K_f =  \frac{1}{2}mv_0^2 + mgh.
</span>
In fact, the total energy of the rock when it <span>leaves the thrower's hand is the sum of the gravitational potential energy U and of the initial kinetic energy K:
</span>E=U_i+K_i=mgh +  \frac{1}{2}mv_0^2
<span>As the rock falls down, its height h from the ground decreases, eventually reaching zero just before hitting the ground. This means that U, the potential energy just before hitting the ground, is zero, and the total final energy is just kinetic energy: 
</span>E=K_f<span>
But for the law of conservation of energy, the total final energy must be equal to the tinitial energy, so E is always the same. Therefore, the final kinetic energy must be
</span>K_f = mgh +  \frac{1}{2}mv_0^2<span>
</span>

7 0
3 years ago
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