Answer:
a) w = 873 rev, b) θ = 97.75 rev
Explanation:
This is a rotation kinematics exercise
w = w₀ + α t
θ = θ₀ + w₀ t + ½ α t²
let's start by reducing the magnitudes to the SI system
w₀ = 300 rpm (2pi rad / 1 rev) (1 min / 60s) = 31.42 rad / s
α = 6 rad / s²
a) let's look for the angular velocity
w = 31.42 + 6 10
w = 91.42 rad / s
b) θ₀ = 0
θ = 0 + 31.42 to + ½ 6 10²
θ = 614.2 rad
As they ask for the result in rpm and revolutions, let's carry out the reduction
w = 91.42 rad / s (1 rev / 2pi rad) (60 s / 1min)
w = 873 rev
θ = 614.2 rad (1 rev / 2pi rad)
θ = 97.75 rev
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