<em><u>Answer</u></em><em><u> </u></em>: HBr polar
<em><u>please</u></em><em><u> </u></em><em><u>add</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>brainalist</u></em>
Electronegativity<span> is the measure of the ability of an atom to attract electrons to itself. Fluorine is the most </span>electronegative<span> element and francium is one of the least</span>electronegative<span>. ... The </span>molecule's polarity<span> will be determined on the negative and positive regions on the outer atoms in the </span>molecule<span>.</span>
we have,
wavelenght=c/f
where c= 3×10^8 m/s
f=6.3×10^12 s^-1
so wavelength=(3×10^8)/(6.3×10^12)
=0.476×10^-4 m
We will use the expression for freezing point depression ∆Tf
∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is
∆Tf = 0C - (-3°C) = 3°C
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and one Cl- ion:
KCl → K+ + Cl-
Therefore, the molality m of the solution can be calculated as
3 = 2 * 1.86 * m
m = 3 / (2 * 1.86)
m = 0.80 molal
Answer:
it's
C. with melting point 11° C and boiling point 181° C
Explanation:
i hope you got it
